How can I prove H(x,y) is a Lyapunov function for this system?

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Discussion Overview

The discussion revolves around proving that the Hamiltonian H(x,y) is a Lyapunov function for a given dynamical system defined by the equations dx/dt = y and dy/dt = 2x - 4x³ - y. Participants explore the conditions under which H can be considered a Lyapunov function, including its time derivative and positivity.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents the Hamiltonian H(x,y) = y² - x² + x⁴ and seeks assistance in proving it as a Lyapunov function.
  • Another participant calculates the time derivative d/dt H(x(t),y(t)) and suggests that it simplifies to -y², indicating that dH/dt < 0, which would imply H is a Lyapunov function.
  • A further contribution suggests that to complete the proof, it must also be shown that H is always positive for nonzero x and y.
  • A final post expresses agreement and appreciation for the discussion.

Areas of Agreement / Disagreement

Participants generally agree on the approach to proving H as a Lyapunov function, but the discussion remains unresolved regarding the complete proof, particularly the positivity condition.

Contextual Notes

The discussion does not clarify the assumptions regarding the values of x and y, nor does it resolve the mathematical steps needed to establish the positivity of H.

squenshl
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Consider the system:
dx/dt = y, dy/dt = 2x - 4x3 - y.

I know that the Hamiltonian H(x,y) = y2/2 - x2 + x4 + y2/2 = y2 - x2 + x4. But how do I show that H is a Lyapunov function for this system. Please help.
 
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Is it:
d/dt H(x(t),y(t)) = d/dt(y2 - x2 + x4) = y dy/dt + dx/dt(-2x + 4x3) = y(2x - 4x3 - y) + y(-2x + 4x3) = 2xy - 4x3y - y2 - 2xy + 4x3y = -y2 < 0. Since dH/dt < 0, this is a Lyapunov function.
 


Also show that H is always positive for nonzero x,y. Then you are done.
 


Cool.
Cheers.
 

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