- #1
JorgeM
- 30
- 6
- TL;DR Summary
- I need to convert an equation that is on polar coordinates into a cartesian but as soon I start doing that I got confused and I'm not really shure about what to do.
I got a polar function.
$$ \psi = P(\theta )R(r) $$
When I calculate the Laplacian:
$$ \ \vec \nabla^2 \psi = P(\theta)R^{\prime\prime}(r) + \frac{P(\theta)R^{\prime}(r)}{r} + \frac{R(r)P^{\prime\prime}(\theta)}{r^{2}}
$$
Now I need to convert this one into cartesian coordinates and then it results very difficult to me because I know how to convert simple equations using the simple relations:$$ x = r Cos(\theta ) $$$$ y = r Sin(\theta ) $$
$$ r= \sqrt{x^{2}+y^{2}} $$
$$ \theta= arcTan( \frac{y}{x}) $$I can't figure out how to use this relations in order to replace them in my functions R and P since there are first and second derivatives of a functions dependent on x and y, so I can not just replace the relations (At least not directly).
What I need to do is to express the Laplacian of psi in cartesian coordinates.
Is there a way just to replace in them as :
$$ P(\theta) = F(x,y)$$
$$ P^{\prime}(\theta) = G(x,y)$$
$$ P^{\prime\prime}(\theta) = H(x,y)$$
Or how should I try?
Thanks A lot for your help
$$ \psi = P(\theta )R(r) $$
When I calculate the Laplacian:
$$ \ \vec \nabla^2 \psi = P(\theta)R^{\prime\prime}(r) + \frac{P(\theta)R^{\prime}(r)}{r} + \frac{R(r)P^{\prime\prime}(\theta)}{r^{2}}
$$
Now I need to convert this one into cartesian coordinates and then it results very difficult to me because I know how to convert simple equations using the simple relations:$$ x = r Cos(\theta ) $$$$ y = r Sin(\theta ) $$
$$ r= \sqrt{x^{2}+y^{2}} $$
$$ \theta= arcTan( \frac{y}{x}) $$I can't figure out how to use this relations in order to replace them in my functions R and P since there are first and second derivatives of a functions dependent on x and y, so I can not just replace the relations (At least not directly).
What I need to do is to express the Laplacian of psi in cartesian coordinates.
Is there a way just to replace in them as :
$$ P(\theta) = F(x,y)$$
$$ P^{\prime}(\theta) = G(x,y)$$
$$ P^{\prime\prime}(\theta) = H(x,y)$$
Or how should I try?
Thanks A lot for your help