How Can I Prove the Property Function of Exponential Matrices?

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Discussion Overview

The discussion revolves around proving the property of exponential matrices, specifically the equation \(\exp(At)\exp(-At_0)=\exp(A(t-t_0))\). Participants explore various mathematical properties and approaches related to this equation, including power series expansions and differentiation techniques.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant asks how to prove the equation \(\exp(At)\exp(-At_0)=\exp(A(t-t_0))\) using properties of exponential matrices and power series.
  • Another participant questions the notation used in the original post, suggesting that the expression \(\exp(At)_t=0\) is incorrectly stated and clarifies that it should be \([\exp(At}]_{t=0} = I\).
  • A participant provides a power series expansion to show that \([\exp(At}]_{t=0} = I\) is valid, indicating that the higher-order terms vanish at \(t=0\).
  • One participant expresses confusion about transitioning from infinite sums to finite sums in the context of the proof and seeks further reading on the topic.
  • Another participant reiterates a link to a resource that they believe contains the necessary proof, suggesting that it may help clarify the question.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the original question. There are multiple interpretations of the notation and differing opinions on the approach to proving the property of exponential matrices.

Contextual Notes

Some participants express uncertainty regarding the notation and the assumptions involved in the proof. The discussion includes references to specific properties of exponential matrices that may depend on the context in which they are applied.

juaninf
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How can prove this

\exp(At)\exp(-At_0)=\exp(A(t-t_0))?

using \displaystyle\sum_{i=0}^n{(1/k!)A^kt^k}

and this properties
in t=0
<br /> [\exp(At)]_{t} = I<br />exp(At)exp(-At)=I
\frac{dexp(At)}{dt}=Aexp(At)=exp(At)A
 
Last edited:
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For your first equation, please refer to this question in http://www.voofie.com/concept/Mathematics/" :

http://www.voofie.com/content/152/how-to-prove-eat-e-at_0-eat-t_0/"

I think you typed wrong in this formula:

exp(At)_t=0 = I

0 is not equal to I. And your what's your meaning of exp(At)_t?

For this one exp(At)exp(-At)=I, you can use my result to prove easily. For the last one, you should try to use the power series expansion and differentiate term by term. You will get the answer easily too.
 
Last edited by a moderator:
juaninf said:
How can prove this
exp(At)_t=0 = I

To conclude, i suppose you mean

[\exp(At)]_{t=0} = I

Well, it's pretty simple:

[\exp(At)]_{t=0} = \left[\sum_{k=0}^\infty\frac{A^kt^k}{k!}\right]_{t=0}=I+0+0+\cdots=I
 
fix question my question is
How prove this,
<br /> \exp(At)\exp(-At_0)=\exp(A(t-t_0))<br />
using as above properties
 
Thank,I am reading this web
http://www.voofie.com/content/152/how-to-prove-eat-e-at_0-eat-t_0/

but i don't understand how change sumatoria infinite to finite, Where i can read this?
 
Last edited by a moderator:
I have answered your question. Please have a look.

http://www.voofie.com/content/152/how-to-prove-eat-e-at_0-eat-t_0/"
 
Last edited by a moderator:

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