How Can I Solve 2^n = 150 / 0.5 for n Using Logarithms?

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Homework Help Overview

The discussion revolves around solving the equation 2^n = 150 / 0.5, specifically focusing on finding the value of the exponent "n" using logarithms. The context is within pre-calculus mathematics, dealing with exponential equations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the use of logarithms as a potential method to isolate "n". There is a suggestion to simplify the equation by dividing 150 by 0.5, leading to a new equation. Some participants question the understanding of logarithms and their application in this context.

Discussion Status

The discussion is ongoing, with some participants providing guidance on using logarithms and simplifying the equation. There is an exploration of the range for "n" based on the values of 2 raised to different powers, but no consensus has been reached on a complete solution.

Contextual Notes

Participants are navigating the constraints of the problem, including the need to apply logarithmic properties and the implications of the equation's setup. There is a mention of homework rules regarding the posting of questions.

n108
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I needed help with this equation:
2^n = 150 / 0.5
I don't know how to solve for the unknown "n" (which in this problem is the number of half lives) if its the exponent of something. what do I do?
 
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Please do not post your questions here. They should be posted in the appropriate forums.

With respect to your question, take logs, that's all there is to it...
 
Thread moved to Homework Help, Pre-Calculus Math.

n108, do you see a way that you could use logarithms to help you solve that equation for n?
 
First thing for you to do is divide 150/.5= 300. Now you have 2n= 300. Now 28= 256 and 29= 512. Since 300 is between 256 and 512, n is between 8 and 9. Do you know about logarithms?
 

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