How can I solve for flow rate and energy savings in a centrifugal fan system?

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SUMMARY

This discussion focuses on calculating flow rate and energy savings in a centrifugal fan system, specifically for a supply fan delivering 2.5 m³/s against a pressure of 500 Pa. Key calculations include determining the operating point using system characteristics, comparing damper control versus speed control, and calculating the required fan speed and potential kW savings from speed control. The use of fan affinity laws is recommended for accurate calculations.

PREREQUISITES
  • Understanding of centrifugal fan performance characteristics
  • Familiarity with fluid dynamics equations, specifically ΔP = c * qv²
  • Knowledge of fan affinity laws and their applications
  • Basic electrical power calculations, including W = qv * ΔPa/η
NEXT STEPS
  • Research fan affinity laws and their implications for centrifugal fan systems
  • Learn how to plot system characteristics and operating points for fans
  • Study the differences between damper control and variable speed drive control
  • Explore energy efficiency calculations for HVAC systems
USEFUL FOR

Mechanical engineers, HVAC technicians, and anyone involved in the design or optimization of centrifugal fan systems will benefit from this discussion.

Howlin
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Hi all
I have the following question that I require help with.

1. Homework Statement

A supply fan must deliver 2.5m3s of air against a system pressure of 500 Pa.The selected fir this has a performance characteristic as listed below when running at a speed of 1800 revs/min.
i) Plot the system characteristic and determine the actual operating point when the fan is connected to the system.

ii) Show using simple sketches the difference between using damper control and speed control to obtain the design flow rates of 2.5m3/s.

iii)Calculate the speed the fan should run at to deliver the design flow rate.

iv) Calculate the kW savings that can be made by using speed controls instead of damper control

Volume Flow Rate (m3/s) ......0.5 1 1.5 2 2.5 3
Pressure drop (Pa) .......800 850 820 740 600 400
Power(kW) ..........0.53 1.1 1.54 1.8 1.88 1.74

2. Homework Equations

Given none but equations I have used:

ΔP = c* qv2

The Attempt at a Solution



i)
c = ΔP/qv2
c = 500/2.52
c = 80

ΔP1 = 80*.52 = 20
ΔP1 = 80*.1.02 =80
ΔP1 = 80*1.52 = 180
ΔP1 = 80*2.02 = 320
ΔP1 = 80*2.52 = 500
ΔP1 = 80*3.02 = 720

I graphed this data and got the following graph:

upload_2015-12-11_16-39-57.png


The lines intersect at approximately 2.6m3/s and 528 kPaI do not know how to work out ii)
but I think they are the following but I don't understand it

Snapshot 1.jpg
Snapshot 2.jpg


iii)
The equation to work out the speed of the fan below but I am unsure which values go in where.
N1 / N2 = F1/F2iv)
The equation to work out the kW savings
W1/ W2 = N1/N2

and work is
W = qv *ΔPa/η

I am unsure how to work this out.
Can anyone help me by nudging me in the right direction? Thank you in advance
Regards,
Stephen
 
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