How can I solve for t using the complete the square method?

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Discussion Overview

The discussion centers around solving the equation t^2 + t = 5.1 using the method of completing the square. Participants explore different approaches to the problem, including alternative methods and the context of the equation.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the equation t^2 + t = 5.1 and seeks a method to solve for t without using a calculator.
  • Another participant suggests that the question should be categorized as homework and mentions the ABC-formula as a solution method.
  • A different participant clarifies that their question is related to initial velocity in a physics context, indicating a more complex application than a straightforward algebraic problem.
  • One participant explains the use of the quadratic formula and provides the necessary transformation of the equation into standard form.
  • Another participant outlines the process of completing the square, detailing the steps to rewrite the equation and solve for t, while noting the addition of a constant to both sides.

Areas of Agreement / Disagreement

Participants express differing views on the categorization of the question and the appropriate methods for solving it. There is no consensus on a single approach, as multiple methods are discussed.

Contextual Notes

Some participants reference the ABC-formula and completing the square, but there is no resolution on which method is preferable or more effective for the given problem. The discussion reflects varying levels of familiarity with algebraic techniques.

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I have an equation which I ended up with as t^2 + t = 5.1

How do I then solve for t (without just plugging it into solve on the calculator)?
 
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This should be in the homework section. You can solve it by using the ABC-formula.
 
Cyosis - The question is not homework so I put it in general math. The actual question I'm trying is one on the initial velocity of an object required to catch another object released a second before it over a 50m displacement. Not that hard if I make my calculator solve it, just making a mess of the algebra because I havn't done it in 8 years.

Anyway will look up the ABC rule.
 
The solution to an equation of the form [itex]ax^2+bx+c=0[/itex] is given by [itex]x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/itex]. To make use of this formula you will have to write [itex]t^2+t=5.1[/itex] as [itex]t^2+t-5.1=0[/itex].
 
Alternatively, you could "complete the square".

For any number, a,
[tex](t- a)^2= t^2- 2at+ a^2[/tex]
You have [itex]t^2+ t= 5.1[/itex] which will match the first two terms of that if 2at= t or a= 1/2. In that case [itex]a^2= 1/4[/itex] so adding 1/4 to both sides of the equation: [itex]t^2+ t+ 1/4= 5.1+ 1/4= 5.1+ .25= 5.35[/itex]

Now that the left side is a "perfect square" you have [itex](t+ 1/2)^2= 5.35[/itex] and you can solve that by taking the square root of both sides (remembering that the result can be either positive or negative).
 

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