How can I solve this first order DE with initial value y(0)=3^(1/2)/2?

[Eastonc2]

The problem:

dx(1-y^2)^1/2=dy(1-x^2)^1/2

y(0)=3^(1/2)/2

My attempt:

I separated the variables and integrated, and came up with

sin^-1(x)+c=sin^-1(y)

This is where i am stuck. any suggestions? did I run astray anywhere?

 

[Ivan92]

You seem to be on the right track. Now given the initial value, plug in 0 for x and 3^(1/2)/2 for y and solve for C. You should take it from there.