How can I solve this problem about factorization in the IB math SL book?

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Homework Help Overview

The problem involves a right-angled triangle with perpendicular sides of lengths x+2 and 5x-3, and a hypotenuse of length 4x+1. The objective is to find the value of x, with the book indicating possible solutions of 2/5 or 3.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the derivation of a quadratic equation, with one individual arriving at 10x^2 - 18x - 12 = 0, while others suggest checking arithmetic errors in the formulation of the equation.

Discussion Status

Some participants have identified potential errors in the quadratic equation derived by the original poster. Guidance has been offered to show work for better understanding, and there is an acknowledgment of mistakes in calculations. Multiple interpretations of the problem setup are being explored.

Contextual Notes

Participants are preparing for the IB exam and are encouraged to engage in the learning process without direct solutions being provided, adhering to forum rules.

richardz03
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Originally posted in a technical math section
It is a problem found on IB math SL book:The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.

I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Later i used quadractic formula and imy result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please! Currently studying for IB exam
 
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richardz03 said:
It is a problem found on IB math SL book:The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.
I get the same answers.
richardz03 said:
I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Check your arithmetic. Your 2nd and 3rd terms are wrong.
richardz03 said:
Later i used quadractic formula and imy result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please! Currently studying for IB exam
No, we aren't going to work the problem for you -- that is against forum rules. Show the work you did to get your equation, and we'll point out where you went wrong, and steer you in the right direction.
 
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richardz03 said:
It is a problem found on IB math SL book:The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.

In the answer section, it says X is either 2/5 or 3.

I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Later i used quadratic formula and my result is totally different to the answers given by the book,. My process should be wrong. I would like to see someone do the complete process so i can notice my error. Please! Currently studying for IB exam
It looks like you made a mistake in getting that quadratic equation.

Try your answers and the book's answers in the given length formulas.
 
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Mark44 said:
I get the same answers.
Check your arithmetic. Your 2nd and 3rd terms are wrong.

No, we aren't going to work the problem for you -- that is against forum rules. Show the work you did to get your equation, and we'll point out where you went wrong, and steer you in the right direction.

Didnt know that! thanks. At least you showed me the error. I will try again then
 
Hmm looks like i got error in doing (4x+1)^2 and did wrong in operation. thanks everyone. No need to respond this thread anymore. It was 10x^2 -34x +12=0
 

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