How Can the Sequence (n^2 +10)/(n^3 -10) Be Proven to Converge to 0?

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Homework Help Overview

The discussion revolves around proving the convergence of the sequence (n^2 + 10)/(n^3 - 10) to 0. Participants are exploring the mathematical reasoning behind convergence in the context of sequences and limits.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to establish convergence by analyzing the sequence's behavior as n approaches infinity. Questions about the specific conditions needed for convergence and the interpretation of bounds are raised.

Discussion Status

There are various lines of reasoning being explored, including bounding the sequence and examining monotonicity. Some participants have provided partial insights into the convergence process, but no consensus has been reached on the final approach or conclusion.

Contextual Notes

Participants are discussing the need for specific values of N in relation to the convergence proof, as well as the implications of bounding and monotonicity in the context of sequences.

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|(n^2 +10)/(n^3 -10)<(n^2 +10)/(n^3)< ..<e

i need some (1/n)<e


??
 
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What's the actual question that you're asking?
 
i need to prove a convergence

i stuck on the last part
i got

n>10/(e-1)what to write about N ??
 
To show it is bounded:

0 < |(n^2 +10)/(n^3 -10)<2(n^2)/(n^2) = 2

To show it converges, try to show that the sequence is monotone, and use the fact that all bounded and monotonic sequences converge. Or, see below:


To show it converges:

[n^2(1 + 10/n^2)] / [n^2(n - 10/n^2)]

= (1 + 10/n^2) / (n - 10/n^2)

the 10/n^2 in both the numerator and denominator converge to 0 and so we have 1/n, which converges to 0 as well.
 
Last edited:

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