How Can Velocity and Angular Momentum Be Calculated in These Dynamics Problems?

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SUMMARY

This discussion focuses on calculating velocity and angular momentum in dynamics problems involving rigid bodies. The user employs the cross-product to derive velocities, specifically using equations such as v_B=\vec{\omega_B} \times \vec{r_{CB}} and v_A=\vec{\omega_A} \times \vec{r_{OA}}. The moment of inertia is calculated using the formula (1/12)mL^2, and the user contemplates the application of the parallel axis theorem for uniform rods. The discussion highlights the importance of correctly identifying angular velocities and forces in dynamic systems.

PREREQUISITES
  • Understanding of vector cross-products in physics
  • Familiarity with angular velocity and moment of inertia calculations
  • Knowledge of the parallel axis theorem
  • Basic principles of dynamics and rigid body motion
NEXT STEPS
  • Study the application of the parallel axis theorem in rigid body dynamics
  • Learn about calculating angular momentum using L = I\omega
  • Explore the relationship between torque and angular acceleration
  • Review examples of rigid body motion problems involving multiple axes
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Students and professionals in physics, mechanical engineering, and applied mathematics who are working on dynamics problems involving rigid bodies and angular motion.

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Homework Statement



http://img18.imageshack.us/img18/4180/82081641.jpg
http://img14.imageshack.us/img14/2650/26169677.jpg


http://img13.imageshack.us/img13/6657/diagramsx.jpg



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The Attempt at a Solution



For the first one, the solutions are different from mine, but here is what I did:

Note [itex]\times[/itex] denotes the cross-product

[tex]v_B=\vec{\omega_B} \times \vec{r_{CB}}[/tex]
[tex]v_B=2.5k \times 0.045j=-0.1125j[/tex]

[tex]v_A=\vec{\omega_A} \times \vec{r_{OA}}[/tex]
[tex]v_A= 3k \times 0.06i=0.18j<br /> <br /> [tex]\vec{v_{AB}}=\vec{v_A}-\vec{v_B}=0.1125i+0.18j[/tex]<br /> <br /> Now, [itex]\vec{r_{AB}}= 0.09i+0.12j[/itex]<br /> <br /> [tex]\vec{\omega_{AB}} \times \vec{r_{AB}}= w_{AB}k \times (0.09i+0.12j)[/tex]<br /> [tex]\Rightarrow \vec{v_{AB}}=-0.12 \omega_{AB}i+0.09\omega_{AB}j[/tex]<br /> <br /> <br /> and if I compare components I get two different values for [itex]\omega[/itex]<br /> <br /> <br /> For the second question, the first thing I'd do is get the moment of inertia of the rod about the centre using (1/12)mL^2 and then say Ia=Torque to get a, then use F=ar to get the force needed. But I do not know if I should assume the rod is uniform and use the parallel axis theorem.<br /> <br /> For the third one, I am not too sure how to start that one. All I know that I can get from reading the question is the moment of inertia about the axis using the radius of gyration.[/tex]
 
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