MHB How Do Angles Relate in Inclined Plane Physics?

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In inclined plane physics, the angles related to a block on an incline are interconnected, specifically the incline angle and the angles formed by the gravitational force vector (Mg) and the force vector (F_2). The incline angle, denoted as θ, is equal to the angle ψ between Mg and F_2 due to the geometric properties of perpendicular vectors. By establishing a horizontal line through the origins of the vectors, it is determined that the angle between the horizontal line and F_2 is 90 - θ. The relationship between these angles shows that ψ + (90 - θ) equals 90, leading to the conclusion that ψ equals θ. Understanding these relationships is crucial for solving problems involving inclined planes in physics.
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In physics, when we draw a block on an incline, we know that the angles are the same see image:

0IzdpxK.png


Incline angle = angle formed by Mg, M, F_2

I can't recall what geometry properties allows us to make this statement.
 
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Imagine drawing a horizontal line through where your 2 blue vectors originate.

Since $F_2$ and the incline are perpendicular, if the angle of the incline is $\theta$, the angle between the horizontal line (going clockwise) and $F_2$ is $90 - \theta$.

Since the horizontal line and vector $Mg$ are also perpendicular the angle between the horizontal line and $F_2$ and the angle between $F_2$ and $Mg$ must sum to 90, so if the angle between $Mg$ and $F_2$ is called $\psi$, we have:

$\psi + 90 - \theta = 90$
$\psi - \theta = 0$
$\psi = \theta$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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