MHB How Do Angles Relate in Inclined Plane Physics?

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In inclined plane physics, the angles related to a block on an incline are interconnected, specifically the incline angle and the angles formed by the gravitational force vector (Mg) and the force vector (F_2). The incline angle, denoted as θ, is equal to the angle ψ between Mg and F_2 due to the geometric properties of perpendicular vectors. By establishing a horizontal line through the origins of the vectors, it is determined that the angle between the horizontal line and F_2 is 90 - θ. The relationship between these angles shows that ψ + (90 - θ) equals 90, leading to the conclusion that ψ equals θ. Understanding these relationships is crucial for solving problems involving inclined planes in physics.
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In physics, when we draw a block on an incline, we know that the angles are the same see image:

0IzdpxK.png


Incline angle = angle formed by Mg, M, F_2

I can't recall what geometry properties allows us to make this statement.
 
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Imagine drawing a horizontal line through where your 2 blue vectors originate.

Since $F_2$ and the incline are perpendicular, if the angle of the incline is $\theta$, the angle between the horizontal line (going clockwise) and $F_2$ is $90 - \theta$.

Since the horizontal line and vector $Mg$ are also perpendicular the angle between the horizontal line and $F_2$ and the angle between $F_2$ and $Mg$ must sum to 90, so if the angle between $Mg$ and $F_2$ is called $\psi$, we have:

$\psi + 90 - \theta = 90$
$\psi - \theta = 0$
$\psi = \theta$.
 
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