How Do Angles Relate in Inclined Plane Physics?

  • Context: MHB 
  • Thread starter Thread starter Dustinsfl
  • Start date Start date
  • Tags Tags
    Angles Geometry
Click For Summary
SUMMARY

The discussion focuses on the relationship between angles in inclined plane physics, specifically how the incline angle, denoted as θ, relates to the angles formed by the gravitational force vector (Mg) and the force vector (F₂). It establishes that the angle ψ between Mg and F₂ is equal to the incline angle θ, derived from the geometric properties of perpendicular vectors. The analysis confirms that the sum of angles formed by these vectors adheres to the principles of geometry, ensuring that ψ + (90 - θ) = 90 leads to the conclusion ψ = θ.

PREREQUISITES
  • Understanding of inclined plane physics
  • Familiarity with vector representation in physics
  • Basic knowledge of geometry, specifically properties of angles and perpendicular lines
  • Ability to interpret and manipulate trigonometric relationships
NEXT STEPS
  • Study the principles of vector decomposition in inclined planes
  • Learn about the role of gravitational forces in physics problems
  • Explore trigonometric identities related to angles in physics
  • Investigate applications of inclined planes in real-world scenarios
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the geometric relationships in inclined plane problems.

Dustinsfl
Messages
2,217
Reaction score
5
In physics, when we draw a block on an incline, we know that the angles are the same see image:

0IzdpxK.png


Incline angle = angle formed by Mg, M, F_2

I can't recall what geometry properties allows us to make this statement.
 
Mathematics news on Phys.org
Imagine drawing a horizontal line through where your 2 blue vectors originate.

Since $F_2$ and the incline are perpendicular, if the angle of the incline is $\theta$, the angle between the horizontal line (going clockwise) and $F_2$ is $90 - \theta$.

Since the horizontal line and vector $Mg$ are also perpendicular the angle between the horizontal line and $F_2$ and the angle between $F_2$ and $Mg$ must sum to 90, so if the angle between $Mg$ and $F_2$ is called $\psi$, we have:

$\psi + 90 - \theta = 90$
$\psi - \theta = 0$
$\psi = \theta$.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
Replies
5
Views
14K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K