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## Homework Statement

how do I factorize (x-1)(x-2)(x-3)(x-4) -48 into (x

^{2}-5x+12)(x

^{2}-5x-2)

## Homework Equations

no relevant equations

## The Attempt at a Solution

I've found the value of (x-1)(x-4) and the value of (x-2)(x-3) first. which is (x

^{2}-5x+4) abd (x

^{2}-5x+6), I put them together and -48 at the end. The problem is, how do I put the -48 inside the brackets?