how do I factorize (x-1)(x-2)(x-3)(x-4) -48 into (x2-5x+12)(x2-5x-2)
no relevant equations
The Attempt at a Solution
I've found the value of (x-1)(x-4) and the value of (x-2)(x-3) first. which is (x2-5x+4) abd (x2-5x+6), I put them together and -48 at the end. The problem is, how do I put the -48 inside the brackets?