jemjabella42 Messages 11 Reaction score 0 Thread starter Jan 16, 2012 #1 How do I take (2/3) x (3 x 10^8)?
Delphi51 Homework Helper Messages 3,406 Reaction score 11 Jan 16, 2012 #2 You could express 2/3 as 0.66666667 and multiply by 3 x 10^8. You could cancel the 3's to get 2 x 10^8 You could multiply the numerators 2 x 3 x 10^8, then divide by the denominator 3.
You could express 2/3 as 0.66666667 and multiply by 3 x 10^8. You could cancel the 3's to get 2 x 10^8 You could multiply the numerators 2 x 3 x 10^8, then divide by the denominator 3.