How do I solve for F in F = 9/5C + 32?

[alg]

How do I solve for F in

View attachment 9570

 

[topsquark]

How do I solve for F in

Hint: Multiply both sides of the equation by 5/9.

-Dan

 

[alg]

Is the following correct?

9/5C = 9/5F - 9/5(1/32)
C = F - 1/32
F = C + 1/32

 

[skeeter]

Is the following correct?

9/5C = 9/5F - 9/5(1/32)
C = F - 1/32
F = C + 1/32

not quite ...

$C = \dfrac{9}{5}(F-32)$

as suggested by topsquark ...

${\color{red}\dfrac{5}{9}} \cdot C = {\color{red}\dfrac{5}{9}} \cdot \dfrac{9}{5}(F-32)$

$\dfrac{5}{9} \cdot C = \cancel{\dfrac{5}{9}} \cdot \cancel{\dfrac{9}{5}} ( F - 32)$ (note that any number times its reciprocal equals 1)

$\dfrac{5}{9} \cdot C = F - 32$

can you finish ?

 

[alg]

F = 9/5C + 32

Thank you!

 

[skeeter]

F = 9/5C + 32

correction ...

$F=\dfrac{5}{9} \cdot C + 32$