How Do Relevant Equations Help Solve Problems?

Thread starter postmalone
Start date Jul 13, 2022

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Relevant equations play a crucial role in problem-solving by providing a framework for understanding the relationships between different variables. They guide the approach to a problem, allowing for systematic analysis and application of mathematical principles. Demonstrating reasonable effort before seeking help is essential, as it shows engagement with the material and helps clarify the specific challenges faced. By articulating one's thought process and the equations considered, individuals can receive more targeted assistance. Ultimately, utilizing relevant equations effectively enhances problem-solving capabilities.

Jul 13, 2022

postmalone

New poster has been reminded to always show their work when starting schoolwork threads

Homework Statement: An interesting problem using capacitors and moving charges in a magnetic field

Relevant Equations: r=mv/qb

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Jul 13, 2022

kuruman

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According to PF rules, you need to show reasonable effort before receiving help. Tell us what you think, how you would approach the problem and what is the role of the "relevant equations" in the solution.

Nevertheless, the answer to the question posed in the title is "Yes, we can solve this problem."

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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