MHB How Do Tensor Products Relate to Supports in Algebraic Geometry?

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The discussion centers on a problem involving locally ringed spaces and the relationship between tensor products and supports of modules in algebraic geometry. It states that for any $\mathscr{O}_X$-modules $\mathscr{F}$ and $\mathscr{G}$ of finite type, the support of their tensor product is equal to the intersection of their individual supports. The problem remains unanswered in the thread, prompting the poster to share their own solution. This highlights the importance of understanding tensor products in the context of algebraic geometry. The discussion invites further exploration and engagement with the topic.
Euge
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Here is this week's POTW:

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Suppose $(X, \mathscr{O}_X)$ is a locally ringed space. Show that for all $\mathscr{O}_X$-modules $\mathscr{F}$ and $\mathscr{G}$ of finite type, $\operatorname{Supp}(\mathscr{F}\otimes_{\mathscr{O}_X} \mathscr{G}) = \operatorname{Supp}(\mathscr{F})\cap \operatorname{Supp}(\mathscr{G})$.-----

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No one answered this week's problem. You can read my solution below.
Let $\mathscr{F}$ and $\mathscr{G}$ be $\mathscr{O}_X$ modules of finite type. If $x\notin\operatorname{Supp}(\mathscr{F}) \cap \operatorname{Supp}(\mathscr{G})$, then either $\mathscr{F}_x = 0$ or $\mathscr{G}_x = 0$. It follows that $\mathscr{F}_x \otimes_{\mathscr{O}_{X,x}} \mathscr{G}_x = 0$, or $(\mathscr{F}\otimes_{\mathscr{O}_X} \mathscr{G})_x = 0$. Thus $x\notin \operatorname{Supp}(\mathscr{F}\otimes_X \mathscr{G})$. Conversely, if $x\notin \operatorname{Supp}(\mathscr{F}\otimes \mathscr{G})$, then $\mathscr{F}_x \otimes_{\mathscr{O}_{X,x}} \mathscr{G}_x = 0$. As $\mathscr{F}$ and $\mathscr{G}$ are of finite type, $\mathscr{F}_x$ and $\mathscr{G}_x$ are finitely generated modules over local ring $\mathscr{O}_{X,x}$. Nakayama's lemma implies $\mathscr{F}_x = 0$ or $\mathscr{G}_x = 0$, i.e., $x\notin \operatorname{Supp}(\mathscr{F}) \cap \operatorname{Supp}(\mathscr{G})$.
 

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