How do we calculate slope of a acceleration vs.time graph?

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SUMMARY

The discussion focuses on calculating the slope of an acceleration vs. time (a-t) graph, specifically in the context of a lab experiment measuring acceleration due to gravity. The user, Roro312, provided data points including average time intervals, total distance, and average velocity, which are essential for constructing the graph. The slope of the a-t graph represents the change in acceleration over time, indicating the behavior of falling objects under gravitational influence. Understanding this relationship is crucial for interpreting motion in physics.

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Roro312
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Im doing a lab about acceleration due to gravity.
And one of the things we had to do is make a a-t graph using the Aave and Ttotal.
Interval ∆t Ttotal ∆d Dtotal Vave ∆v Aave(cm/s^2)
1 0.050 0.050 2.0 2.0 40 - -
2 0.050 .100 4.0 6.0 80 40 800
3 0.050 .150 6.8 12.8 136 56 1120
4 0.050 .200 8.5 21.3 170 34 680
5 0.050 .250 11.0 32.3 220 50 1000
6 0.050 .300 13.9 46.2 278 58 1160
7 .050 .350 15.5 61.7 310 32 640
8 .050 .400 17.4 79.1 348 38 760

my graph looks something like this [PLAIN]http://www.kwantlen.bc.ca/...ebtests/xtgraphquiz/images/image002[/PLAIN] .

My question is how do we calculate slope on a a-t graph and what does this slope tell us about falling objects. Thanks
 
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tiny-tim said:
Hi Roro312! Welcome to PF! :smile:


Your link isn't working. :redface:

How about this: http://img370.imageshack.us/img370/9488/96191446sb5.jpg
It looks similar to it
 
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