How do we determine the convergence at the endpoints for the series (x-1)^n/n^3?

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SUMMARY

The discussion focuses on determining the convergence at the endpoints for the series ∑(x-1)ⁿ/n³ using the root test. The root test indicates that the interval of convergence is 0 < x < 2, but the necessity of testing the endpoints x = 0 and x = 2 is questioned. It is clarified that a root test result of 1 does not guarantee convergence, as demonstrated by counterexamples such as ∑1 and ∑rⁿ/n. Therefore, endpoint testing is essential to ascertain the behavior of the series at the boundaries of the interval.

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  • Understanding of series convergence tests, particularly the root test.
  • Familiarity with the concept of intervals of convergence.
  • Basic knowledge of infinite series and their properties.
  • Ability to analyze series behavior at specific points.
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GreenPrint
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Hi,

I don't really need help with a problem, just having some troubles understanding something.

Find the interval of convergence of the series

sigma[n=0,inf] (x-1)^n/n^3
by the root test I got that |x-1|<1 and that 0<x<2
I than have to plug in these values (0 and 2) to see if the series converges or diverges at these endpoints... I however am confused by this. If we set x = 0 or x = 2 wouldn't the root test give us 1 and the root test states that if the limit equals one than the series converges. So what's the need of testing the end points? Like I know we have to just am not really sure why because than the root test would give us 1... I never understood why we test the end points and just sort of did so just because I was told we had to and was wondering if someone could explain this to me. I hope someone can clear up this confusion for me. Thanks for any help!
 
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GreenPrint said:
Hi,

I don't really need help with a problem, just having some troubles understanding something.

Find the interval of convergence of the series

sigma[n=0,inf] (x-1)^n/n^3
by the root test I got that |x-1|<1 and that 0<x<2
I than have to plug in these values (0 and 2) to see if the series converges or diverges at these endpoints... I however am confused by this. If we set x = 0 or x = 2 wouldn't the root test give us 1 and the root test states that if the limit equals one than the series converges. So what's the need of testing the end points? Like I know we have to just am not really sure why because than the root test would give us 1... I never understood why we test the end points and just sort of did so just because I was told we had to and was wondering if someone could explain this to me. I hope someone can clear up this confusion for me. Thanks for any help!

Root test = 1 does NOT guarantee convergence. Look at sum_{n=1}^infinity 1. Does it converge? Does it satisfy root test = 1? Look at sum r^n /n. Root test implies convergence for |r| <= 1. Does the series converge at r = 1? At r = -1?

RGV
 
Well like I forgot myself and had to look up on wikipedia http://en.wikipedia.org/wiki/Root_test and it says that if r=1 than the series diverges so I thought it was always |r| < 1 not |r| <= 1?
 
If n=1 when using the root test, it means your answer is inconclusive AKA use another test (that's what RGV is hinting at).
 
hm interesting thanks
 
Sorry that I didn't answer your second question, if {n&lt;1} it will ALWAYS converge, if {n&gt;1} it will ALWAYS diverge! If {n&lt;=1} then I'm going to guess that it'll converge, but I've never seen a series that has n<=1!

This is for ratio/root test.
 

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