MHB How do we solve a quadratic inequality with multiple factors?

  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Quadratic
AI Thread Summary
To solve the quadratic inequality (x^4)(x - 2)(x - 16) ≥ 0, critical points are identified by setting each factor to zero, resulting in x = 0, x = 2, and x = 16. The root x = 0 has an even multiplicity, meaning the sign of the expression remains unchanged across this point, while the others have odd multiplicities, indicating a sign change. Testing intervals around the critical points reveals that the solution set is (-infinity, 2] U [16, infinity). The approach of plotting the critical points on a number line and testing intervals is confirmed as correct. This method effectively identifies where the inequality holds true.
mathdad
Messages
1,280
Reaction score
0
This is the last quadratic inequality problem (for now) before moving on to Chapter 3, Section 3.1 THE DEFINITION OF A FUNCTION.

Section 2.6
Question 30

Solve the quadratic inequality.

(x^4)(x - 2)(x - 16) ≥ 0

Do I set each factor to 0 and solve for x? The values of x are then plotted on the number line for testing.

Correct?
 
Mathematics news on Phys.org
RTCNTC said:
This is the last quadratic inequality problem (for now) before moving on to Chapter 3, Section 3.1 THE DEFINITION OF A FUNCTION.

Section 2.6
Question 30

Solve the quadratic inequality.

(x^4)(x - 2)(x - 16) ≥ 0

Do I set each factor to 0 and solve for x? The values of x are then plotted on the number line for testing.

Correct?

Yes, observe that the root $x=0$ is of even multiplicity (4), and so the sign of the expression will not change across this root. The others are of odd multiplicity (1) and so the sign will change across those roots.
 
I will work on this tomorrow. Working right now.
 
(x^4)(x - 2)(x - 16) ≥ 0

Our critical points are x = 0, x = 2 and x = 16.

I can see that our critical points are also included.

<-------(0)--------(2)--------(16)------>

For (-infinity, 0), let x = -1. True statement.

For (0, 2), let x = 1. True statement.

For (2, 16), let x = 3. False statement.

For (16, infinity), let x = 4. True statement.

Solution:

(-infinity, 2] U [16, infinity)

Correct?
 
Last edited:
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top