How Do You Calculate Efficiency in a Carnot Cycle Involving Argon?

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stonecoldgen
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Homework Statement


its part VI) of a big problem, where:

0.12 moles of argon (40) undergoes the cycle abca described in the graph. Process ab lies on a 540k isotherm.

In the previious 5 sub problems, i figured that:

Tc=270k
Qbc=670J (lost)
Qca=400J (added)
Wab=370J
Wabca=100J


The PV diagram has points a,b and c where:

a=(1.5X10-3, 3.6X105)
b=(3X10-3, 1.8X105)
c=(1.5X10-3, 1.8X105)







Homework Equations



Q=mc[itex]\Delta[/itex]T

[itex]\Delta[/itex]U=Q+W

[itex]\epsilon[/itex]=1-Qout/Qin=1-Tlow/Thigh

The Attempt at a Solution


So it's basically using Qabca to find the efficiecy. The thing is that I am not sure what to use for the Qs.
 
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What is Qs supposed to represent? I don't see it in your problem statement.
 
RTW69 said:
What is Qs supposed to represent? I don't see it in your problem statement.

it's a plural for Q, I am not sure what to use for Qin and Qout
 
Remember this is NOT a carnot cycle. η= 1- Qout/Qin There is also a Qin between A and B. Do you know what it is? It is the Qout/ the Total Qin.