How Do You Calculate Relative Error in Mass Measurement?

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To calculate the mass of air in a room with given dimensions and density, the volume is determined as 40 m³, leading to a mass of approximately 0.03 kg. The relative error for the mass is derived from the individual relative errors of the measured quantities. Since the density has a relative error of 5% and each dimension has a 10% relative error, the total relative error for the mass is calculated by adding these errors together. Thus, the relative error for the mass would be 5% + 10% + 10% + 10%, resulting in a total relative error of 35%. Understanding how to combine relative errors is crucial for accurate mass measurement calculations.
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Assume the density of air was measured as 1.00 kg/m3 ± 5%. The room has dimensions 4 m × 5 m × 2 m, each measured with 10% relative error. What is the mass of the air in the room? What is the relative error for the mass?

I think this is a very simple problem, and i found what the mass of the air would be, i just don't understand relative errors, so how do i find the relative error for the mass?

D = m/V D = 1.00 kg/m3 V = (4 m *5 m *2 m) = 40 m3
m = (1.00 kg/m3)/ (40 m3)
m = .025 kg → m = .03 kg

relative error: Is it something like 5%/ 10% ??
 
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Have you studied the rule for how to get the relative error when you multiply two quantities?
 
no, we didn't learn much about relative error at all.
 
Have a look at this page:

http://www.rit.edu/~uphysics/uncertainties/Uncertaintiespart2.html

I myself don't know that much about how to treat relative errors... but it seems like when you multiply quantities you add relative errors.

In your calculation there are 4 quantities being multiplied. density, length, width, height... so I'm guessing you just add the relative errors to get the relative error of the mass...
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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