How Do You Calculate the 12th Root of x to the Fourth Power?

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Discussion Overview

The discussion centers around the mathematical expression for the 12th root of x to the fourth power, specifically how to simplify and understand the expression 12√x^4. Participants explore the implications of having a root that is larger than the exponent and the related mathematical concepts.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant expresses confusion about how to calculate the 12th root of x to the fourth power, questioning the implications of the root being larger than the exponent.
  • Another participant explains that the expression can be simplified using exponent laws, showing that ##\sqrt[12]{x^4}## can be rewritten as ##x^{1/3}##.
  • A later reply emphasizes that the original question is more about simplification rather than solving an equation.
  • Some participants discuss the importance of understanding mathematical jargon and encourage asking questions as a way to learn.
  • One participant suggests that the question might indicate a deeper concern related to calculus, noting that while exact values can be expressed, numerical approximations may be necessary for irrational results.

Areas of Agreement / Disagreement

Participants generally agree on the simplification of the expression, but there is a divergence in views regarding the implications of the question and its relation to calculus. The discussion remains somewhat unresolved regarding the deeper concerns behind the original question.

Contextual Notes

There are limitations regarding the assumptions made about the values of x and the context in which the expression is applied. The discussion does not resolve the broader implications of the mathematical concepts involved.

EvilScientist
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TL;DR
Finding the root to an exponent that's larger than the root.
I feel incredibly stupid for not getting this. I found this math problem in the beginning of my precalculus book:

12√x^4

That's 12th root of x to the fourth power. How do I find the root of x if the root is larger than the exponent?
 
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EvilScientist said:
Summary: Finding the root to an exponent that's larger than the root.

I feel incredibly stupid for not getting this. I found this math problem in the beginning of my precalculus book:

12√x^4

That's 12th root of x to the fourth power. How do I find the root of x if the root is larger than the exponent?
LaTeX is your friend. See the link to our tutorial in the lower left corner of the input window.

##\sqrt[12]{x^4}## can be rewritten as ##(x^4)^{1/12} = x^{4/12} = x^{1/3}## using the usual laws of exponents. A simpler form of your expression is ##\sqrt[3] x##.

And technically, this is not something to "solve," an action that we can apply to equations or inequalities. What I did was to simplify the expression you wrote.
 
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Mark44 said:
LaTeX is your friend. See the link to our tutorial in the lower left corner of the input window.

##\sqrt[12]{x^4}## can be rewritten as ##(x^4)^{1/12} = x^{4/12} = x^{1/3}## using the usual laws of exponents. A simpler form of your expression is ##\sqrt[3] x##.

And technically, this is not something to "solve," an action that we can apply to equations or inequalities. What I did was to simplify the expression you wrote.
Thank you! It makes a lot more sense to me now. I haven't done this stuff in years and I am trying to brush off my math skills before taking any classes. Needless to say, my math skills are very rusty. Thanks again, I really appreciate it. I'll try learning how to use LaTeX, I'm probably going to need it later.
 
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EvilScientist said:
I'll try learning how to use LaTeX
Start now! Its like riding a bicycle...maybe less fun to learn.
 
Hi, @EvilScientist , could your question hide a deeper concern? Calculus. I mean, nobody knows the value of ##\sqrt[12]{x^{4}}##, if ##x=25##, for instance. Only knows can approximate.
LaTeX is fun
 
Nothing to feel stupid about here. This is really just an issue with not knowing the jargon of that sort of math. We are all stupid about the stuff we haven't learned yet. Go forth and be stupid, ask questions, that's how we all learned this stuff.
 
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mcastillo356 said:
Hi, @EvilScientist , could your question hide a deeper concern? Calculus. I mean, nobody knows the value of ##\sqrt[12]{x^{4}}##, if ##x=25##, for instance. Only knows can approximate.
This has nothing to do with calculus -- ##\sqrt[12]{25^{4}} = \sqrt[3]{25}## is the exact value, but this happens to be irrational, so writing it as a decimal number will be only an approximation. BTW, ##\sqrt[3]{25}## is little less than 3.
 
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