How Do You Calculate the Frequency of Microwaves Using Standing Waves?

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SUMMARY

The frequency of microwaves can be calculated using the formula derived from the standing wave pattern created by incident and reflected waves. In this discussion, a distance of 15 cm between the first and eleventh minima leads to a wavelength (λ) of 0.03 meters, resulting in a frequency of 1 x 1010 Hz when using the velocity of microwaves at 3 x 108 m/sec. Additionally, the ratio of amplitudes at an antinode and a node in a stationary wave is discussed, with the conclusion that the ratio is infinite due to the maximum amplitude at the antinode and minimum displacement at the node.

PREREQUISITES
  • Understanding of standing wave patterns
  • Knowledge of wave velocity and frequency calculations
  • Familiarity with the concept of nodes and antinodes in wave mechanics
  • Basic proficiency in scientific notation
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  • Study the principles of wave interference and superposition
  • Learn about the mathematical derivation of wave frequency from wavelength
  • Explore the characteristics of standing waves in different mediums
  • Investigate the effects of amplitude on wave behavior in stationary waves
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Amith2006
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Sir,
1)Microwaves are directed normally at a plane metallic reflector. A detector moving along the normal to the reflector travels 15 cm from the first to the 11th successive of minimum intensity. What is the frequency of the microwave?(velocity of microwaves = 3 x 10^8 m/sec)
I solved it in the following way:
The incident and the reflected microwaves superimpose to produce standing waves. The distance between the first and the 11th minimum is given that it is 15 cm.
Therefore,
0.15 = 10 x (lambda/2)
Lambda = 0.03 meters
Frequency = (3 x 10^8)/ 0.03
= 10^10 Hz
Is it right?
2)Two waves of same frequency travel in opposite directions in a medium with amplitudes 3 units and 2 units respectively. What is the ratio of the amplitudes at an antinode and a node in the stationary wave?
I think it is infinity because at the antinode it has maximum amplitude and at the node it is zero. Is it right?
 
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Amith2006 said:
Sir,
1)Microwaves are directed normally at a plane metallic reflector. A detector moving along the normal to the reflector travels 15 cm from the first to the 11th successive of minimum intensity. What is the frequency of the microwave?(velocity of microwaves = 3 x 10^8 m/sec)
I solved it in the following way:
The incident and the reflected microwaves superimpose to produce standing waves. The distance between the first and the 11th minimum is given that it is 15 cm.
Therefore,
0.15 = 10 x (lambda/2)
Lambda = 0.03 meters
Frequency = (3 x 10^8)/ 0.03
= 10^10 Hz
Is it right?

This looks good to me. Just a small point however, using standard scientific notation it is better to quote the answer as 1x1010 Hz. However, both are correct.

Amith2006 said:
2)Two waves of same frequency travel in opposite directions in a medium with amplitudes 3 units and 2 units respectively. What is the ratio of the amplitudes at an antinode and a node in the stationary wave?
I think it is infinity because at the antinode it has maximum amplitude and at the node it is zero. Is it right?

Are you sure about that? The formal definition of a node is "a point of minimum displacement.", this need not to be zero. The important thing to note is the respective amplitudes, try sketching the two waves in anti-phase on the same graph.

~H
 

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