How Do You Calculate Velocity and Energy in an Elastic Collision?

Click For Summary

Homework Help Overview

The problem involves two blocks, A and B, undergoing an elastic collision on a frictionless surface. Block A has a mass of 3.50 kg and is initially moving at 9.00 m/s towards block B, which has a mass of 10.00 kg and is at rest. The objective is to find the maximum energy stored in spring bumpers during the collision and the velocities of both blocks at the time of collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between elastic potential energy and kinetic energy, questioning whether they are equal at the moment of collision. There is an attempt to use conservation of momentum and energy equations to find the velocities and energy stored in the springs.

Discussion Status

Some participants have provided hints regarding the relationship between the velocities of the blocks at maximum compression of the springs, suggesting that the relative velocity of the blocks is zero at that point. Others have expressed confusion about the equations and the number of unknowns involved in the problem.

Contextual Notes

Participants are navigating the complexities of elastic collisions, including the conservation of momentum and energy principles, while also grappling with the implications of spring compression in the context of the problem.

irun4edmund
Messages
14
Reaction score
0

Homework Statement


Blocks A (mass 3.50 kg) and B (mass 10.00 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block A is moving toward it at 9.00 m/s. The blocks are equipped with ideal spring bumpers. The collision is head-on, so all motion before and after the collision is along a straight line. Let +x be the direction of the initial motion of A.

Find the maximum energy stored in the spring bumpers and the velocity of each block at the time of the collision.


Homework Equations


K = 0.5mv2
Wnet = Kf - Ki

The Attempt at a Solution


Since the block A is the only block in motion wouldn't the elastic potential energy be equal to the kinetic energy? I tired using 0.5m(v)^2 and setting that equal to the Kinetic energy, but i didn't get the right answer (i got 141.75).

As far as solving for the velocity of blocks A and B, I'm not sure how to go about it. i tried using Vaf = [(3.5-10.0) / 13.5] * 9.00 = 4.3 but this is the velocity of block A right after the collision not during (answer to another part of the question, but it doesn't help me with the first part).

Any help on this would be greatly appreciated. thanks guys.
 
Physics news on Phys.org
Welcome to PF!

irun4edmund said:
Find the maximum energy stored in the spring bumpers and the velocity of each block at the time of the collision.

Since the block A is the only block in motion wouldn't the elastic potential energy be equal to the kinetic energy?

Hi irun4edmund! Welcome to PF! :smile:

No, elastic PE = KE before minus KE after.

Hint for velocities: when the spring is at maximum compression, what is the relative velocity of the blocks?
 
ok i tried PE = 0.5mavai2 -0.5mavaf2-0.5mbvbf2 and got 3.55 J. That wasn't right either...

If the compression of the springs was at an maximum, wouldn't the relative velocities be zero? that was my intial guess and that wasn't right either.
 
Last edited:
irun4edmund said:
If the compression of the springs was at an maximum, wouldn't the relative velocities be zero? that was my intial guess and that wasn't right either.

Hi irun4edmund! :smile:

That is correct … then you combine vaf = vbf with conservation of momentum to find what they are. :smile:
 
Oh.. my.. god. It worked. I never would have thought to set Va = Vb I though i was working 2 equations with 3 unknowns.

I got Va = Vb = 2.33 m/s

Elastic Potential = 105 J

Thank you!
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
Replies
20
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 15 ·
Replies
15
Views
4K
Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K