How Do You Determine Turning Points and Concavity for y=(x^3)/(x^2-1)?

[bruno87]

Homework Statement

need to find the turning points an concavity of this equation. y=(x^3)/(x^2-1),

Homework Equations

i know y'=(x^2(x^2-3))/((x^2-1)^2)
and y''=(2x(x^2+3))/((x^2-1)^3)

need to know the turning points and concavity

The Attempt at a Solution

 

[tiny-tim]

Welcome to PF!

Hi bruno87 ! Welcome to PF!

(try using the X² tag just above the Reply box )

i know y'=(x^2(x^2-3))/((x^2-1)^2)
and y''=(2x(x^2+3))/((x^2-1)^3)

need to know the turning points and concavity]

The turning points should be easy …

what's the test for turning points? ​

 

[bruno87]

just need to know what the answer is

 

[Integral]

Wrong answer.

Thread locked