How Do You Determine Turning Points and Concavity for y=(x^3)/(x^2-1)?

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Homework Help Overview

The discussion revolves around determining the turning points and concavity of the function y=(x^3)/(x^2-1). Participants are exploring calculus concepts related to derivatives and their implications for the behavior of the function.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster presents the derivatives of the function and seeks assistance in identifying turning points and concavity. Some participants inquire about the criteria for determining turning points.

Discussion Status

The conversation includes attempts to clarify the process for finding turning points, with some guidance offered on what to consider. However, there is no explicit consensus on the methods to be used, and the discussion appears to be in an exploratory phase.

Contextual Notes

There is an indication of a lack of clarity regarding the approach to finding the required information, and one participant expresses a desire for a direct answer. The thread has been locked, suggesting a need for adherence to forum guidelines.

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Homework Statement


need to find the turning points an concavity of this equation. y=(x^3)/(x^2-1),


Homework Equations


i know y'=(x^2(x^2-3))/((x^2-1)^2)
and y''=(2x(x^2+3))/((x^2-1)^3)

need to know the turning points and concavity

The Attempt at a Solution

 
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Welcome to PF!

Hi bruno87 ! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)
bruno87 said:
i know y'=(x^2(x^2-3))/((x^2-1)^2)
and y''=(2x(x^2+3))/((x^2-1)^3)

need to know the turning points and concavity]

The turning points should be easy …

what's the test for turning points? :smile:​
 
just need to know what the answer is
 
Wrong answer.

Thread locked
 

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