recoil33
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Solved, thank you.
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The discussion focuses on calculating the center of gravity of a non-uniform plank supported by three trestles. The plank is 4.00 meters long, with vertical reactions of 1.00 x 102N and 3.00 x 102N at the ends, and 4.00 x 102N at the middle. To find the center of gravity, participants confirm that the moment of forces equation should be used instead of a simple mass-based equation. The correct approach involves ensuring that the sum of the moments of the forces acting on the beam equals zero.
PREREQUISITESStudents in physics, engineers involved in structural analysis, and anyone interested in mechanics and the behavior of non-uniform materials.
recoil33 said:Three trestles support a 4.00m long plank, of non-uniform density, one at each end and one at the middle. These exert vertical reactions of 1.00 x 10^2N and 3.00 x 10^2N at the ends, and 4.00 x 10^2N at the middle. Calculate
A) The position of the centre of gravity.
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Could i use this equation to calculate the centre of gravity?
R = (m1r1 + m2r2 + m3r3) / (m1 + m2 + m3)