How Do You Find the Center of Gravity of a Non-Uniform Plank?

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SUMMARY

The discussion focuses on calculating the center of gravity of a non-uniform plank supported by three trestles. The plank is 4.00 meters long, with vertical reactions of 1.00 x 102N and 3.00 x 102N at the ends, and 4.00 x 102N at the middle. To find the center of gravity, participants confirm that the moment of forces equation should be used instead of a simple mass-based equation. The correct approach involves ensuring that the sum of the moments of the forces acting on the beam equals zero.

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recoil33
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Solved, thank you.
 
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Hi recoil33! :smile:
recoil33 said:
Three trestles support a 4.00m long plank, of non-uniform density, one at each end and one at the middle. These exert vertical reactions of 1.00 x 10^2N and 3.00 x 10^2N at the ends, and 4.00 x 10^2N at the middle. Calculate

A) The position of the centre of gravity.

Could i use this equation to calculate the centre of gravity?

R = (m1r1 + m2r2 + m3r3) / (m1 + m2 + m3)

Sort-of …

but you're not actually using masses, are you?

Technically, you should be using a moment of forces equation: the sum of the moments of the four forces on the beam (three reaction forces and the weight) has to be zero. :wink:
 

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