- #1

JuanC97

- 48

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Hello, I just want to clarify some things with a simple exercise: I have the equation ## \frac{\partial^2 f}{\partial A^\mu \,\partial A^\nu} = 0## and I want to integrate it once assuming that ## f=f(A^1,A^2,...,A^n)=f(A^\rho) ##.

I think the solution should be ## \frac{\partial f}{\partial A^\mu} = C_1(A^{\rho\neq\mu}) + (1-\delta_{\mu\nu})\,C_2(A^{\rho\neq\nu}) ##

where ##C_1## and ##C_2## are functions that have to be determined by initial/boundary conditions, the first term came from the integral wrt ##A^\nu## when ##\mu=\nu## and the second one when ##\mu\neq\nu##.

The big confusion arises when I think...

1. Does this really make any sense? - It just looks weird.

2. If ## \frac{\partial f}{\partial A^\mu} ## were a covariant tensor, it would make a lot more sense if I had written ## h(A_\mu) ## instead of ## h(A^\mu) ##, wouldn't it?.

I think the solution should be ## \frac{\partial f}{\partial A^\mu} = C_1(A^{\rho\neq\mu}) + (1-\delta_{\mu\nu})\,C_2(A^{\rho\neq\nu}) ##

where ##C_1## and ##C_2## are functions that have to be determined by initial/boundary conditions, the first term came from the integral wrt ##A^\nu## when ##\mu=\nu## and the second one when ##\mu\neq\nu##.

The big confusion arises when I think...

1. Does this really make any sense? - It just looks weird.

2. If ## \frac{\partial f}{\partial A^\mu} ## were a covariant tensor, it would make a lot more sense if I had written ## h(A_\mu) ## instead of ## h(A^\mu) ##, wouldn't it?.

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