How Do You Solve a Second Order Nonlinear Autonomous ODE?

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SUMMARY

The discussion focuses on solving the second-order nonlinear autonomous ordinary differential equation (ODE) given by y'' = -1/(y^2). The solution involves a transformation where y' is substituted with z, leading to the equation z dz/dy = -1/y^2. By integrating both sides, the problem can be simplified and solved by transforming back to the original variable y and performing a second integration. This method leverages the translational symmetry inherent in autonomous equations.

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MHD93
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Hel(lo, p)

I hope you're doing fine

I'm stuck with the following:

[itex]y'' = -1/(y^2)[/itex]

I tried guessing functions (exponentials, roots, trigs... ) , but none worked, I haven't had any DE course, so I don't have specific steps to employ,

I appreciate your help,
Thanks in advance
 
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the case where [itex]y^{''}=f(y,y^{'})[/itex] is called an autonomous equation (x does not occur directly in the right-hand side).

It can be solved by performing a simple transformation (this transformation follows from a translational symmetry of the ODE)

Let [itex]y^{'}=z[/itex], then
[itex]y^{''}=z^{'}=\frac{dz}{dx}=\frac{dz}{dy}\frac{dy}{dx}=\frac{dz}{dy}z[/itex]
and the equation can be written as:
[itex]z\frac{dz}{dy}=-\frac{1}{y^2}[/itex]
[itex]\int z dz=-\int \frac{1}{y^2}dy[/itex],
then transform back to the original variable y and integrate again.
 

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