The equation \( e^{x-1} = 5 - y^2 + y \) can be solved for \( x \) by applying the natural logarithm. The solution is expressed as \( x = \ln(5 - y^2 + y) + 1 \). It is crucial to ensure that the expression \( 5 - y^2 + y > 0 \) holds, which imposes specific constraints on the values of \( y \). A common error noted in the discussion was the incorrect representation of the solution as \( x = \ln(..) - 1 \) instead of the correct form.
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thank you very much for the help man :)Delta² said:Nope, just mind one thing, you have to include a constraint that 5-y2+y>0 which holds only if y satisfies an inequality regarding its values.
Btw i just noticed one small "typo", it should be x=ln(..)+1 not -1...