How Do You Solve for Q in a Complex Algebra Equation?

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SUMMARY

The discussion focuses on solving the quadratic equation derived from the formula (Fr²)/k = (6.63E-6 - q)q, where Fr²/k represents a known constant. Participants confirm that the equation can be rearranged into the standard quadratic form (aq² + bq + c = 0) for solving q. It is emphasized that factoring is impractical due to the complexity of the coefficients, and attention must be paid to the physical constraints on the value of q.

PREREQUISITES
  • Understanding of quadratic equations and their standard form
  • Familiarity with algebraic manipulation techniques
  • Knowledge of physical properties affecting variable constraints
  • Basic proficiency in using scientific notation
NEXT STEPS
  • Study the methods for solving quadratic equations, including the quadratic formula
  • Explore the implications of physical constraints on algebraic solutions
  • Learn about the application of scientific notation in complex equations
  • Investigate common pitfalls in algebraic manipulation of equations
USEFUL FOR

Students, educators, and professionals in mathematics or engineering fields who are dealing with complex algebraic equations and require a solid understanding of quadratic solutions.

jmb07
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how do i go about solving for q in the equation:

(F x r x r)/k = (6.63E-6 -q)(q)
 
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What are your knowns/unknowns and are there any additional equations?

I skimmed over your other thread, and you're trying to solve for q where the rest of the variables are known, right?

[tex]\frac{Fr^2}{k}=(6.63*10^{-6} -q)q[/tex]
This is just a simple quadratic equation. Using factoring here obviously won't be useful since the numbers are a bit messy. Just arrange it to the general form ([tex]aq^2+bq+c=0[/tex]) and solve for q, and remember any limits you may have on its value because of its physical properties.
 

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