How to Prove a Complex Inequality with Complex Algebra

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SUMMARY

The discussion focuses on proving the complex inequality |1+ab| + |a + b| ≥ √(|a²-1||b²-1|) involving two complex numbers, a and b. Participants suggest factoring the left-hand side to facilitate the proof, specifically using the expression |(a-1)(a+1)(b-1)(b+1)|. The conversation emphasizes the importance of rearranging and recombining factors to explore potential solutions in complex algebra.

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  • Understanding of complex numbers and their properties
  • Familiarity with complex algebra techniques
  • Knowledge of inequalities in mathematical proofs
  • Ability to manipulate algebraic expressions
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  • Research methods for proving inequalities in complex analysis
  • Learn about factorization techniques in complex algebra
  • Study the properties of absolute values in complex numbers
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Mathematics students, educators, and anyone interested in advanced algebraic techniques and complex analysis proofs.

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Homework Statement


Let b and a be two complex numbers. Prove that
|1+ab| + |a + b| ≥ √(|a²-1||b²-1|).

Homework Equations


Complex algebra

The Attempt at a Solution


I don't know how to proceed. I posted it here to get some ideas :p
 
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Try factoring the left hand side:
$$|a^2 - 1||b^2 - 1| = |(a-1)(a+1)(b-1)(b+1)|$$
Now see what happens if you rearrange the factors and recombine them.
 

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