MHB How Do You Solve Linear Equations with Given Coordinates?

  • Thread starter Thread starter Sarahq
  • Start date Start date
AI Thread Summary
To solve linear equations using given coordinates, identify the slope (m) by calculating the change in y over the change in x, which is -2 in this case. The linear equation is structured as y = mx + b, where m represents the slope and b is the y-intercept. By substituting known values into the equation, you can solve for b, resulting in the equation y = -2x + 3. Finally, to find specific values, set y to the desired number and solve for x. This method provides a clear approach to determining linear relationships from coordinates.
Sarahq
Messages
1
Reaction score
0
16368478379993046955366016216983.jpg
 
Mathematics news on Phys.org
Hi Sarahq, and welcome to MHB!

For your Problem 5, you should notice that as $X$ increases by $1$, $Y$ decreases by $2$. So the equation between $X$ and $Y$ should start as $Y = \dfrac{-2}1X \ldots$. You should then be able to find the constant term to complete the equation.
 
Hi Sarahq,

The formula for linear equations is
\[ y = mx+b \]
m = slope and b = shift on the y-axis.

The following formula is used to calculate the slope m
\[ m = \frac{y_2-y_1}{x_2-x_1} \]
(here -2/1 = -2)
Use x-, y-values and m to calculate b:
\[ -23 = -2 * 13 + b \]
solve for b:
\[ -23 = -26 + b | +26 \]
\[ 3 = b \]
so:
\[ y = -2x + 3 \]
Now just set y = 31 and solve for x.
Hope it was helpfull :)
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top