How Do You Solve Projectile Motion Problem #2?

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SUMMARY

The discussion focuses on solving a projectile motion problem involving a rock thrown from a building. The rock's initial velocity is 25 m/s, and it impacts the ground after 3 seconds. Key calculations include the horizontal distance from the building (75 m), the building's height (45 m), the impact velocity (39.05 m/s at an angle of 50.19° below the horizontal), and the distance from the top of the building to the landing point (87.46 m). The use of gravitational acceleration at 9.8 m/s² is emphasized for accurate results.

PREREQUISITES
  • Understanding of kinematic equations, specifically d=vit + (1/2)at²
  • Knowledge of trigonometric functions, particularly tan(theta) = opp/adj
  • Familiarity with vector components in projectile motion
  • Basic grasp of gravitational acceleration, specifically 9.8 m/s²
NEXT STEPS
  • Review the derivation and application of kinematic equations in projectile motion
  • Learn about vector decomposition in two-dimensional motion
  • Explore the effects of varying gravitational acceleration on projectile trajectories
  • Practice additional projectile motion problems with different initial velocities and angles
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone looking to improve their problem-solving skills in kinematics.

phys1618
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Please help! projectile motion problem #2

Homework Statement


A girl throws a rock straight out form the roof of a building. the rock has a velocity of 25 m/s when it leaves the girl's hand, and the rock hits the ground 3 seconds later.
1. how far from the bas e of the building does the rock land?
2. how tall is the building?
3. with what velocity does the rock hit the ground?
4. how far from the top of the builidng does the rock land?



Homework Equations



d=vit + (1/2)at2
c2= a2 + b2
tan theta= opp/adj
a=(vf-vi)/t

The Attempt at a Solution



I'm unsure if my answers are correct. however, I tried and this is what i got
1. 75m
2. 45m
3. 39.05 m/s at 50.19o below ground
4. 87.46m (this is the one I'm really unsure about)

all help and inputs are greatly appreciated. thank you for your time and efforts.
 
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phys1618 said:

Homework Statement


A girl throws a rock straight out form the roof of a building. the rock has a velocity of 25 m/s when it leaves the girl's hand, and the rock hits the ground 3 seconds later.
1. how far from the bas e of the building does the rock land?
2. how tall is the building?
3. with what velocity does the rock hit the ground?
4. how far from the top of the builidng does the rock land?



Homework Equations



d=vit + (1/2)at2
c2= a2 + b2
tan theta= opp/adj
a=(vf-vi)/t

The Attempt at a Solution



I'm unsure if my answers are correct. however, I tried and this is what i got
1. 75m
2. 45m
3. 39.05 m/s at 50.19o below ground
4. 87.46m (this is the one I'm really unsure about)

all help and inputs are greatly appreciated. thank you for your time and efforts.

For 2, if you used 10 as acceleration of gravity then that would be correct. But the more correct answer would use gravity as 9.8m/s2

I get a different answer for 3 by about 7 degrees but I think that may have to do with your treatment of part 2. I would guess your method is ok.
Part 4 is good enough for Government work.

Cheers.
 

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