How Do You Solve Systems of Equations Using an Inverse Matrix?

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This discussion focuses on solving systems of equations using an inverse matrix, specifically the example of the equations -10x - 6y = 6 and 7x + y = -7. The matrix representation of the system is given as Ax = b, where A is the coefficient matrix. The inverse of matrix A can be calculated using the formula A^{-1} = (1/(ad - bc)) * [d, -b; -c, a]. The discussion also suggests using row operations to convert the matrix into an identity matrix to find the inverse, which is particularly useful for larger matrices.

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  • Familiarity with calculating matrix inverses.
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  • Learn how to compute matrix inverses using the formula A^{-1} = (1/(ad - bc)) * [d, -b; -c, a].
  • Explore the method of using row operations to find the inverse of larger matrices.
  • Study the Cramer Method for solving systems of equations.
  • Investigate Gaussian elimination techniques for solving linear systems.
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TonyC
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How would I go about solving a systme of equations using an inverse matrix?

i.e. -10x - 6y = 6
7x + y = -7
 
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As I`m sure this is stated in your book (it should be), this system of equations is equivalent to the single matrix equation:

\left( \begin{array}{cc} -10 & -6 \\ 7 & 1\end{array}\right)\left( \begin{array}{c} x \\ y \end{array}\right)=\left( \begin{array}{c} 6 \\ -7 \end{array}\right)

In general, you can write a linear system of n equations in n unknowns as a matrix equation Ax=b. If you can find the inverse of A (let's call it C, so that CA=AC=I) you have solved the problem, just put x=Cb, then A(Cb)=(AC)b=b.
 
Your question was "How would I go about solving a systme of equations using an inverse matrix?" Are you saying you don't have any problem with actually finding the inverse matrix?
 
Not exactly sure what I am saying. I am not having trouble with any other methods,
i.e. Cramer Method, Gaussian, elementary row operations. This one has me truly stumped. Maybe I'm too tied (or old) to grasp it today.
 
Still trying to figure this out
 
So can you find the inverse of A?
If:
A:= \left[ \begin{array}{cc} a & b \\ c & d \end{array} \right]
Then:
A ^ {-1}= \frac{1}{ad - bc} \left[ \begin{array}{cc} d & -b \\ -c & a \end{array} \right]
After finding the inverse of A, note that:
Ax = b \Leftrightarrow A ^ {-1}Ax = A ^ {-1}b \Leftrightarrow x = A ^ {-1}b
Viet Dao,
 
Although the above method will work (for finding the inverse), you might want to try it a different way. It will help when you get to larger matrices (at least until you learn the generalized form of the above equation).

\left[\begin{array}{cc|cc}a & b & 1 & 0 \\ c & d & 0 & 1\end{array}\right]

Use row operations to make the left side (your original matrix) the identity matrix, and what is left on the right will be the inverse. You are basically saying A\mathbf{x}=I\implies\mathbf{x}=A^{-1}.
 
SHOW YOUR WORK first.
 
I posted the work I have been doing with Matrices previously, thanks for your concern
 

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