How does (AlK(SO4)2•12H2O) balance?

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Discussion Overview

The discussion revolves around the chemical behavior of (AlK(SO4)2•12H2O) in water, including its dissolution and potential reactions. Participants explore related compounds such as (NaCH3COO) and (Cu(NO3)2•2.5H2O), seeking clarifications on acid-base interactions and ion dissociation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant inquires about the reaction of (AlK(SO4)2•12H2O) with water, suggesting a possible reaction with AlOH and H2SO4.
  • Another participant questions the nature of the reaction being asked, prompting clarification on whether it involves dissolution or dissociation.
  • A participant clarifies that the discussion pertains to the dissolution and dissociation of the compound in water.
  • It is noted that the dissociation involves separating ions, with participants identifying Al3+, K-, and SO4 2- as components of the alum molecule.
  • One participant corrects the identification of K- as a valid ion, indicating that it does not exist in this context.
  • There is a mention of cation hydrolysis and the formation of complexes involving Al3+, with one participant stating that there are at least four equilibrium reactions associated with Al3+ in solution.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the reaction and the relevance of complex formation involving Al3+. There is no consensus on the specific reactions or products formed in the dissolution process.

Contextual Notes

Some participants express uncertainty regarding the details of cation hydrolysis and the complexity of the reactions involving Al3+, indicating that these may not be necessary for understanding at an introductory level.

Who May Find This Useful

This discussion may be useful for students new to chemistry, particularly those interested in acid-base reactions and the behavior of ionic compounds in solution.

jigglywiggly
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So like say you have (AlK(SO4)2•12H2O)
And then how does the reaction go?

Is it like (AlK(SO4)2•12H2O) -> AlOH + H2SO4 or something like this?

Was also wondering how like
(NaCH3COO) would work with H2O as well...
same for this
(Cu(NO3)2•2.5H2O)

These are acid-base, and I am pretty new to them, could I get some clarifications? Thanks
 
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jigglywiggly said:
So like say you have (AlK(SO4)2•12H2O)
And then how does the reaction go?

What reaction?

Please ask homework (and homework type) questions in appropriate forum.
 
Sorry, and It's just reacting with plain o'll water.
 
So you are asking about dissolution and dissociation.

In most cases dissociation is just about separating ions. What ions do you see in the alum molecule?

Don't worry about water of crystallization - it will just became part of the solution, there is already plenty of water around.
 
Just Al3+ K- and SO4 2-
 
No such thing as K-.

So if you have Al3+, why do you try to put something like AlOH between products?

Are you expected to know all the details of cation hydrolysis in such solutions?
 
Yeah I believe so.
 
That's a tricky thing - Al3+ creates a series of complexes, 4 at least (or rather I have equilibrium constants for 4 reactions). But these are things like Al3(OH)45+ - I don't think anybody by graduate students should worry about them.
 

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