How Does Constant Yield Harvesting Affect Fish Population Stability?

  • Context: MHB 
  • Thread starter Thread starter alane1994
  • Start date Start date
  • Tags Tags
    Dynamics population
Click For Summary
SUMMARY

The discussion centers on the impact of constant yield harvesting on fish population stability, specifically using a logistic growth model. The differential equation governing the fish population is given by \(\frac{dy}{dt}=r(1-\frac{y}{K})y-h\), where \(h\) represents the constant harvesting rate. The analysis reveals two equilibrium points, \(y_1\) and \(y_2\), with \(y_1\) being unstable and \(y_2\) asymptotically stable when \(h < \frac{rK}{4}\). Understanding these dynamics is crucial for formulating effective fishery management strategies.

PREREQUISITES
  • Understanding of logistic growth models in population dynamics
  • Familiarity with differential equations and stability analysis
  • Knowledge of equilibrium points and their significance in dynamical systems
  • Basic concepts of fishery management and sustainable harvesting practices
NEXT STEPS
  • Study the implications of varying harvesting rates on fish population dynamics
  • Explore the concept of stability in nonlinear differential equations
  • Investigate alternative harvesting strategies and their ecological impacts
  • Learn about the application of phase plots in analyzing dynamical systems
USEFUL FOR

Ecologists, fisheries scientists, and mathematical biologists interested in population dynamics and sustainable resource management will benefit from this discussion.

alane1994
Messages
36
Reaction score
0
Hey MHB, I have this rather large and convoluted project that consists of two problems. I have finished the first problem that consisted of 4 parts. I am working through the second part right now. It has a preamble that is kinda important. I will post that as well as the problems that I am working on.

Harvesting a Renewable Resource

Suppose that the population \(y\) of a certain species of fish (e.g., tuna or halibut) in a given area of the ocean is described by the logistic equation

$$\displaystyle\frac{dy}{dt}=r(1-\frac{y}{K})y$$

If the population harvested is subjected to harvesting at a rate \(H(y,t)\) members per unit time, then the harvested population is modeled by the differential equation

$$\displaystyle\frac{dy}{dt}=r(1-\frac{y}{K})y-H(y,t)$$

Although it is desireable to utilize the fish as a food source, it is intuitively clear that if too many fish are caught, then the fish population may be reduced below a useful level and possibly even driven to extinction. The following problems explore some questions involved in formulating a rational strategy for managing the fishery.

Problem 1)
This problem was based upon effort involved in harvesting. I can post this question along with my work for it if you guys are interested.

Problem 2)
This is the problem that I am currently working on.

Constant Yield Harvesting
In this problem, we assume that fish are caught at a constant rate \(h\) independent of the size of the fish population, that is, the harvesting rate \(H(y,t)=h\). Then\(y\) satisfies

\(\displaystyle\frac{dy}{dt}=r(1-\frac{y}{K})y-h~~~~~~~(ii)\)

The assumption of a constant catch rate \(h\) may be reasonable when \(y\) is large but becomes less so when \(y\) is small.

(a) If \(h<rK/4\) shows that Eq.(ii) has two equilibrium points \(y_1\) and \(y_2\) with \(y_1<y_2\); determine these points.

My work,

\(\displaystyle f(y)=\frac{dy}{dt}=r(1-\frac{y}{K})y-h\)

\(\displaystyle ry(1-\frac{y}{K})-h=0\)

\(\displaystyle -\frac{ry^2}{K}+ry-h=0\)

\(\displaystyle y^2-yK+\frac{hK}{r}=0\)

\(\displaystyle y^2-yK=-\frac{hK}{r}\)

\(\displaystyle y^2-yK+\frac{K^2}{4}=\frac{K^2}{4}-\frac{hK}{r}\)

\(\displaystyle (y-\frac{K}{2})^2=\frac{K^2}{4}-\frac{hK}{r}\)

\(\displaystyle y-\frac{K}{2}=\sqrt{\frac{K^2}{4}-\frac{hK}{r}}\)

\(\displaystyle y=\frac{K}{2}\pm\sqrt{\frac{K^2}{4}-\frac{hK}{r}}\)(b) Show that \(y_1\) is unstable and \(y_2\) is asymptotically stable.

This part is giving me some trouble. I think I would just calculate the second derivative of the original diff.eq and then you would plug in the two points found just above right?

Any help would be appreciated!
 
Physics news on Phys.org
I agree with the equilibrium points you have found:

$$y_1=\frac{K}{2}-\sqrt{\frac{K^2}{4}-\frac{hK}{r}}$$

$$y_2=\frac{K}{2}+\sqrt{\frac{K^2}{4}-\frac{hK}{r}}$$

Now, regarding the stability of the equilibrium, consider that the phase plot will look something like:

View attachment 1652

Disregard the actual numbers on the axes, just consider that the plot of $$\frac{dy}{dt}$$ is a function of $y$ and has two positive roots (the equilibrium points) and is parabolic, opening downward.

Can you tell by looking at the plot how $$\frac{dy}{dt}$$ will behave near these equilibrium points?

For example, look at $y_1$, the smaller root. Below this root, in what direction are the solutions going? How about above this root? In both cases, are they being attracted to or repelled away from this point?
 

Attachments

  • phaseplot.jpg
    phaseplot.jpg
    5.3 KB · Views: 173

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 4 ·
Replies
4
Views
1K