How Does Cyclic Product Change for Polynomial Roots?

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SUMMARY

The discussion centers on evaluating the cyclic product $$\prod_{\text{cyclic}}\frac{a-1}{a+1}$$ for the roots $a, b, c$ of the polynomial $P(x) = x^3 - 2007x + 2002$. Participants successfully solved the problem, with notable contributions from members castor28, greg1313, lfdahl, and kaliprasad. The solution provided by greg1313 outlines the necessary steps and calculations to arrive at the final result.

PREREQUISITES
  • Understanding of polynomial roots and their properties
  • Familiarity with cyclic products in algebra
  • Knowledge of Vieta's formulas for relating coefficients and roots
  • Basic skills in algebraic manipulation and simplification
NEXT STEPS
  • Study Vieta's formulas in depth to understand relationships between polynomial coefficients and roots
  • Explore cyclic products and their applications in algebra
  • Learn about polynomial root evaluation techniques
  • Investigate advanced algebraic identities related to polynomial expressions
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Mathematicians, algebra students, and educators interested in polynomial theory and root evaluation techniques will benefit from this discussion.

anemone
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Here is this week's POTW:

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If $a,\,b$ and $c$ are roots of the polynomial $P(x) = x^3 - 2007x + 2002$, evaluate $$\prod_{\text{cyclic}}\frac{a-1}{a+1}$$.

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Remember to read the https://mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to https://mathhelpboards.com/forms.php?do=form&fid=2!
 
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Congratulations to the following members for their correct solution!(Cool)

1. castor28
2. greg1313
3. lfdahl
4. kaliprasad

Solution from greg1313:
Using Vieta's formulas,

$$\prod_{\text{cyclic}}\frac{a-1}{a+1}=\frac{(a-1)(b-1)(c-1)}{(a+1)(b+1)(c+1)}=\frac{abc-ab-ac-bc+a+b+c-1}{abc+ab+ac+bc+a+b+c+1}=\frac{-2002+2007+0-1}{-2002-2007+0+1}=\boxed{-\frac{1}{1002}}$$
 

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