How Does Force Affect Javelin Momentum and Speed?

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The discussion focuses on calculating the increase in momentum and speed of a javelin thrown by a 75kg athlete applying a force of 300 N for 1.5 seconds. The impulse-momentum theorem states that the change in momentum is equal to the force applied multiplied by the time duration, leading to an increase in momentum of 450 kg·m/s. Consequently, the speed of the javelin immediately after the throw is determined to be 225 m/s, given that the initial momentum is zero.

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A 75kg javelin thrower applies a 300 N force to a 2.0kg javelin for 1.5 seconds.

a)what is the increase in momentum of the javelin?

b)what is the speed of the javelin immediately after the throw?

all i know is that ft = /\(mv) /\ is suppose to be a triangle.
 
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Look up the relation between change in momentum and impulse.
 
Hint: the initial momentum is zero
 

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