Undergrad How does gauge pressure affect the buoyant force on a submerged object?

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Gauge pressure (pg) affects buoyant force by influencing the density of the fluid in which an object is submerged. The buoyant force is equal to the weight of the displaced fluid, which depends on the fluid's density. While density increases with pressure, the change is minimal for liquids like water due to low compressibility, as indicated by the bulk modulus. At depths of 20,000 feet, gauge pressure can exceed 9,000 psi, but the resulting increase in buoyant force is negligible, only a few percent. Thus, gauge pressure has a minimal impact on buoyant force except at extreme depths.
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How can we relate gauge pressure (pg) to the buoyant force , in a completely submerged object?
is it as follow: Buoyant force= pg.Area +Density(water).volume.gravity ?
 
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How can we relate gauge pressure (pg) to the buoyant force , in a completely submerged object? is it as follow: Buoyant force= pg.Area +Density(water).volume.gravity ?

The buoyant force on a submerged object is equal to the weight of the volume of the fluid displaced. This weight depends on the density of the fluid. In so far as the density increases with pressure the buoyant force will increase. But density increases only very slowly for liquids which is determined by its compressibility which is determined by its Bulk Modulus. For water for example the density increases only a few percent at a depth of 20,000 ft, so the buoyant force will only increase by this amount. Gauge pressure will have increase from zero to over 9,000 psi at this depth. So the buoyant force can be related to gauge pressure by the equation

BF = density @ zero GP *Volume( 1 + GP/EB)

Where EB is the bulk modulus of the fluid: For water it is 3.1x105 lbs/in2

So you see GP makes negligible difference in BF except at extreme depths.
 
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