How Does Kinetic Friction Affect Motion on a Level Surface?

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SUMMARY

The discussion centers on calculating the coefficient of kinetic friction for a 1400 N crate being pushed across a level surface with a 300 N force at a 20.0° angle below the horizontal. The coefficient of kinetic friction can be determined using the formula: μ_k = F_f / N, where F_f is the frictional force and N is the normal force. Additionally, the discussion addresses the scenario where the force is applied at a 20.0° angle above the horizontal, requiring the calculation of the crate's acceleration under the same friction conditions.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of friction coefficients and their calculations
  • Familiarity with vector components of forces
  • Basic algebra for solving equations
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  • Study the calculation of frictional forces in physics problems
  • Learn how to resolve forces into their components
  • Explore the effects of angle on force application in motion
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Students in physics courses, particularly those tackling problems involving friction and motion, as well as educators seeking to clarify these concepts for their students.

Lmbrando
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Hi I need help on my homework and i have no idea where to start and my teacher gives us webassign problems but he does not teach us how to do them, he just gives us formulas.. If anyone can help me with at least this problem i'd appreciate it thx

p.s I am struggling help!



A 1400 N crate is being pushed across a level floor at a constant speed by a force of 300 N at an angle of 20.0° below the horizontal, as shown in Figure P4.37a.



(a) What is the coefficient of kinetic friction between the crate and the floor?

(b) If the 300 N force is instead pulling the block at an angle of 20.0° above the horizontal as shown in Figure P4.37b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in (a).
m/s2
 
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Hi there Lmbrando and welcome to PF,

Have you any thoughts on the matter thus far?
 

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