How Does Magnetic Field Orientation Affect Torque on a Solenoid?

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Homework Help Overview

The discussion revolves around calculating the torque exerted on a solenoid placed in a uniform magnetic field. The solenoid has specific parameters including the number of turns, current, and cross-sectional area, and the magnetic field strength is given. The problem specifically examines two orientations of the solenoid relative to the magnetic field: perpendicular and at a 45-degree angle.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the torque formula τ = IBAsinθ and question the correctness of the area used in calculations. There is also exploration of the impact of angle on torque results.

Discussion Status

Some participants have provided guidance on correcting the area measurement, noting that it should be converted from cm² to m². Others express uncertainty about their calculations and seek confirmation of their results.

Contextual Notes

Participants are navigating the conversion of units and the implications of using different angles in the torque formula. There is a focus on ensuring the accuracy of the parameters used in the calculations.

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Torque on a soleniod / coil in magnetic field

Homework Statement



A solenoid having 180 turns and a cross-sectional area of 6.68 cm2 carries a current of 1.12 A

1) If it is placed in a uniform 1.12 T magnetic field, find the torque this field exerts on the solenoid if its axis is oriented perpendicular to the field.

2) If it is placed in a uniform 1.12 T magnetic field, find the torque this field exerts on the solenoid if its axis is oriented at 45.0* with the field

Homework Equations



τ = IBAsinθ

The Attempt at a Solution



1) know the following:
N=180 , B = 1.12T , I = 1.12A , θ = 90* , area = .0668 m2

τ = IBAsinθ

τ = (1.12 A) (1.12 T) ( .0668 m2) (sin90) = 0.084
I then take that and multiply by number of turns = 0.084 x 180 = 15.08

But my answer is wrong. where am I going wrong?



2) N=180 , B = 1.12T , I = 1.12A , θ = 45* , area = .0668 m2

τ = IBAsinθ

τ = (1.12 A) (1.12 T) ( .0668 m2) (sin45) = 0.060
I then take that and multiply by number of turns = 0.060 x 180 = 10.67

This is also a wrong answer. Where am I going wrong here?


Please help
 
Last edited:
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Hi jvince17,

jcvince17 said:

Homework Statement



A solenoid having 180 turns and a cross-sectional area of 6.68 cm2 carries a current of 1.12 A

1) If it is placed in a uniform 1.12 T magnetic field, find the torque this field exerts on the solenoid if its axis is oriented perpendicular to the field.

2) If it is placed in a uniform 1.12 T magnetic field, find the torque this field exerts on the solenoid if its axis is oriented at 45.0* with the field

Homework Equations



τ = IBAsinθ

The Attempt at a Solution



1) know the following:
N=180 , B = 1.12T , I = 1.12A , θ = 90* , area = .0668 m2

This area is not correct. Remember that the area given in the problem was in cm2, not cm. Do you see what it need to be?
 


alphysicist said:
Hi jvince17,



This area is not correct. Remember that the area given in the problem was in cm2, not cm. Do you see what it need to be?


I sure do! thank you very much. I changed my area and recalculated and both answers are now correct!
 
Good evening,

This is my first time doing this since i had just completed my registration. I am really very eager to know exactly my answer to the problem because when i tried solving it for number 1 my answer is (0) because i am using (cos 90) which is equal to 0. In number 2 my answer is 0.1066522483 N.m. I do not know if I am correct. If I am wrong please I need to know where did I get it wrong.

Thank you very much and more power to us!
 

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