How Does Modular Arithmetic Relate to Odd Prime Numbers?

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SUMMARY

This discussion focuses on the relationship between modular arithmetic and odd prime numbers, specifically addressing the condition where an odd prime \( p \) divides \( b^2 + 1 \). It establishes that if \( p \) divides \( b^2 + 1 \), then \( p \equiv 1 \mod 4 \). The participants also highlight that the order of \( b \) is 4 modulo \( p \), reinforcing the connection between even numbers and their squares in modular contexts.

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Daveyboy
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b>1, p an odd prime

b2 = -1 mod p

if p|b2 + 1
show p = 1 mod 4

I know that the order of b is 4 (mod p)
 
Last edited:
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That's a strange approach to use...
I would do it this way: Since p is odd, and p|a^2 + 1, a must be an even number. a^2 thus = 0 (mod 4), and consequently a^2 + 1, and p are both congruent to 1 (mod 4)
 
haha, oh man it's so obvious, I can't believe I missed it.
 

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