How Does One Calculate Z from Electric Field Equations?

[nerdsamurai22]

solve for $z$
$$R=.13m$$
$$r=.026$$
$$\sigma=6.20 \cdot 10^{-12}C/m^2$$
$$\epsilon= 8.85 \cdot 10^{-12}$$

$$\frac{6.20\cdot 10^{-12}C/m^2}{8.85\cdot 10^{-12}N-m^2/C^2} \cdot \sqrt{(R^2+z^2)-z})- \sqrt{(r^2+z^2)-z})$$

 

[Prove It]

Re: how to solve for z

solve for z
R=.13m
r=.026
sigma=6.20x10^-12C/m^2
epsilon= 8.85x10^-12

{[6.20x10^-12C/m^2]/[8.85x10^-12N-m^2/C^2]}*sqrt[(R^2+z^2)-z])- sqrt[(r^2+z^2)-z])

This is so hard to read. For one thing, I can't tell if $\displaystyle \begin{align*} C/m^2 \end{align*}$ is a unit or is part of the term, and if it IS part of the term, I can't tell whether any of it is a part of the power of 10.

Please use brackets where they're needed at the very least.

Also, I don't see how it's possible to solve for z when this isn't even an equation...

 

[I like Serena]

Re: how to solve for z

I've taken the liberty to convert to formulas to latex.
That leaves 2 unbalanced parentheses and a unit for $\epsilon$ that is inconsistent, that I don't know what to do with.