MHB How Does One Calculate Z from Electric Field Equations?

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To calculate z from the given electric field equations, the formula involves parameters such as R, r, σ, and ε. The equation presented is complex and lacks clarity due to formatting issues, making it difficult to discern whether certain terms are units or part of the equation. There are concerns about unbalanced parentheses and inconsistent units, particularly for ε. The discussion highlights the need for clearer notation and proper use of brackets to improve readability. Overall, resolving these formatting issues is essential for accurately solving for z.
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solve for $z$
$$R=.13m$$
$$r=.026$$
$$\sigma=6.20 \cdot 10^{-12}C/m^2$$
$$\epsilon= 8.85 \cdot 10^{-12}$$

$$\frac{6.20\cdot 10^{-12}C/m^2}{8.85\cdot 10^{-12}N-m^2/C^2} \cdot \sqrt{(R^2+z^2)-z})- \sqrt{(r^2+z^2)-z})$$
 
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Re: how to solve for z

nerdsamurai22 said:
solve for z
R=.13m
r=.026
sigma=6.20x10^-12C/m^2
epsilon= 8.85x10^-12

{[6.20x10^-12C/m^2]/[8.85x10^-12N-m^2/C^2]}*sqrt[(R^2+z^2)-z])- sqrt[(r^2+z^2)-z])

This is so hard to read. For one thing, I can't tell if $\displaystyle \begin{align*} C/m^2 \end{align*}$ is a unit or is part of the term, and if it IS part of the term, I can't tell whether any of it is a part of the power of 10.

Please use brackets where they're needed at the very least.

Also, I don't see how it's possible to solve for z when this isn't even an equation...
 
Re: how to solve for z

I've taken the liberty to convert to formulas to latex.
That leaves 2 unbalanced parentheses and a unit for $\epsilon$ that is inconsistent, that I don't know what to do with.
 
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