How Does Pascal's Principle Apply in Hydraulic Systems?

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Homework Statement



A 200 kg object sits on a 3.0 m2 piston that is connected to a hydraulic system with a 0.5 m2 piston attached. What is the pressure under the 3.0 m2 piston? What is the pressure under the 0.5m2 piston and why? What force needs to be applied to the smaller piston to move the object?


The Attempt at a Solution



For the pressure under the 3.0 m2 piston. I used P=F/A
P=(200*9.8)/3
P=653 Pa

Is this rite? or should i use 3.0+0.5 for A?

for the other pressure i said it was the same because of Pascal's principle.

As for the last part i did F1A1=F2A2
so F2=(F1A1)/A2
F2=(200*9.8*0.5)/3
=327N

I'm not sure if i did this right. any help/comment would help a lot.
 
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chukie said:

Homework Statement



A 200 kg object sits on a 3.0 m2 piston that is connected to a hydraulic system with a 0.5 m2 piston attached. What is the pressure under the 3.0 m2 piston? What is the pressure under the 0.5m2 piston and why? What force needs to be applied to the smaller piston to move the object?


The Attempt at a Solution



For the pressure under the 3.0 m2 piston. I used P=F/A
P=(200*9.8)/3
P=653 Pa

Is this rite? or should i use 3.0+0.5 for A?

for the other pressure i said it was the same because of Pascal's principle.

As for the last part i did F1A1=F2A2
so F2=(F1A1)/A2
F2=(200*9.8*0.5)/3
=327N

I'm not sure if i did this right. any help/comment would help a lot.
Looks good to me :approve:
 

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