How Does Re[s]>0 Relate to Laplace Sine Transform Conditions?

  • Context: Graduate 
  • Thread starter Thread starter back2square1
  • Start date Start date
  • Tags Tags
    Laplace Sine Transform
Click For Summary
SUMMARY

The discussion centers on the conditions for the Laplace Sine Transform, specifically L[sin(at)] = a/(s² + a²) with the requirement that Re[s] > 0. It highlights the relationship between the conditions s > ia and s < -ia, emphasizing that these conditions ensure the real part of s is greater than zero, which is necessary for the existence of the integral. The discussion clarifies that while complex numbers are not ordered, the real part's positivity is crucial for the transform's validity.

PREREQUISITES
  • Understanding of Laplace Transforms
  • Familiarity with complex analysis
  • Knowledge of integral convergence criteria
  • Basic proficiency in mathematical notation and operations
NEXT STEPS
  • Study the properties of Laplace Transforms in detail
  • Explore complex analysis, focusing on the ordering of complex numbers
  • Investigate integral convergence and its implications in transform theory
  • Learn about the implications of the real part of complex variables in mathematical analysis
USEFUL FOR

Mathematicians, engineers, and students studying control systems or signal processing who require a deeper understanding of Laplace Transforms and their conditions for validity.

back2square1
Messages
13
Reaction score
0
L[sin(at)]=\frac{a}{s^{2}+a^{2}}, Re<s>&gt;0</s>

L[e^{kt}]=\frac{1}{s-k}, s&gt;k
L[e^{-kt}]=\frac{1}{s+k}, s&lt;-k

L[sin(at)]=\frac{1}{2i}L[e^{iat}-e^{-iat}]
=\frac{1}{2i}L[e^{iat}]-L[e^{-iat}]
Using the above relations
=\frac{1}{2i}[\frac{1}{s-ia}-\frac{1}{s+ia}], s&gt;ia, s&lt;-ia

The problem is that I don't understand, how s>ia and s<-ia could imply that Real part of s>0?
 
Physics news on Phys.org
Complex numbers are not ordered,
s>ia and s<-ia
does not make sense.
Real part of s>0
Is needed to assure the existence of the integral.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
2
Views
2K