- #1

ChiralSuperfields

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- Homework Statement
- Please see below

- Relevant Equations
- ##L[(\cos^2 (2t)] = L[\cos 2t] * L[\cos 2t]##

For part (b),

I have tried finding the Laplace transform of via the convolution property of Laplace transform.

My working is,

##L[\cos^2 (2t)] = L[\cos 2t] * L[\cos 2t]##

##L[\cos^2 (2t)] = \frac{s}{s^2 + 4} * \frac{s}{s^2 + 4}##

##\int_0^t \frac{s^2}{(s^2 + 4)^2} dt = \frac{ts^2}{(s^2 + 4)^2}##

However, I don't see how that is equivalent/equal to the expression they got for (b). Does some please know how or if I've made a mistake?

Thanks!

I have tried finding the Laplace transform of via the convolution property of Laplace transform.

My working is,

##L[\cos^2 (2t)] = L[\cos 2t] * L[\cos 2t]##

##L[\cos^2 (2t)] = \frac{s}{s^2 + 4} * \frac{s}{s^2 + 4}##

##\int_0^t \frac{s^2}{(s^2 + 4)^2} dt = \frac{ts^2}{(s^2 + 4)^2}##

However, I don't see how that is equivalent/equal to the expression they got for (b). Does some please know how or if I've made a mistake?

Thanks!