How Does the Angle Impact Force Calculation in Newton's Second Law Problems?

Ammar w
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Homework Statement



http://www.diigo.com/item/image/2sb3i/ahcq

Homework Equations



Ʃ[itex]\vec{F}[/itex] = m[itex]\vec{a}[/itex]

The Attempt at a Solution



For M :
T - mg = ma
T - 19.6 = 2a (1)

For 2M :
40 cos (150) - T = 4a
from (1) : T = 2a + 19.6
substituting :
40 cos (150) - (2a +19.6) = 4a
40 cos (150) - 19.6 = 6a

a = [itex]\frac{40 cos (150) - 19.6}{6}[/itex] = -9 m/s^2

but the right answer is 2.5 m/s^2.
if I replace 150 with 30 the answer will be correct
but it's 150 with respect to the positive x axis.
what is the wrong please??
 
Last edited by a moderator:
What is direction of T for 2M?
 
The sign of F cos 150 does not match what you've assumed in your equation.
 

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