How Does the Constant '2' Arise in Binomial Theorem Equalities?

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SUMMARY

The equality in question arises from the binomial theorem, specifically the identity $\sum_{k=0}^n\binom{n}{k}=2^n$. This identity can be understood through combinatorial proofs, which count the number of subsets of a set of size $n$. Each element in the set has two choices: to be included in a subset or not, leading to a total of $2^n$ subsets. Various proof techniques exist, including induction and differentiation, which further validate this equality.

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gladeligen
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Hi!

My first post!

I was wondering if anyone could explain this equality in words?
I do not understand how the k became a constant (2) on the right side?Best
Flippa
 

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Hi, and welcome to the forum!

Proving equalities in words is not something mathematicians usually do. They usually prove equalities by a series of formulas. Perhaps the most intuitive type of proofs of similar facts is combinatorial proofs, where you consider a set and count its size in two different ways. You can find one such proof on StackExchange. It relies on the fact that $\sum_{k=0}^n\binom{n}{k}=2^n$. This fact also has a combinatorial proof: $\binom{n}{k}$ is the number of subsets of size $k$ of the set of size $n$, so the left-hand side is the number of all subsets of a set of size $n$. This number is known to be $2^n$ because each of the $n$ elements either occurs in a subset or does not (thus $n$ consecutive independent yes/no choices). There are many other proofs of the same fact on the SE page and pages linked therein: some use induction, others differentiation, etc.
 

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