How Does the Proton-Proton Cycle Result in the Formation of Helium?

  • Thread starter Thread starter logearav
  • Start date Start date
  • Tags Tags
    Cycle Proton
Click For Summary
SUMMARY

The proton-proton cycle involves the fusion of six protons to ultimately produce two helium-4 nuclei, along with the release of energy, positrons, and neutrinos. Initially, two protons fuse to create deuterium, which then combines with another proton to form helium-3. Two helium-3 nuclei subsequently fuse to yield helium-4 and release two protons. The net reaction can be simplified to 61H → 4He + 21H, demonstrating the conservation of hydrogen nuclei throughout the process.

PREREQUISITES
  • Understanding of nuclear fusion processes
  • Familiarity with the proton-proton cycle in stellar nucleosynthesis
  • Knowledge of particle interactions, specifically positrons and neutrinos
  • Basic grasp of chemical reaction equations and conservation laws
NEXT STEPS
  • Study the detailed mechanisms of the proton-proton cycle in stellar environments
  • Learn about the role of energy release in nuclear fusion
  • Explore the implications of neutrinos in astrophysics and particle physics
  • Investigate other fusion processes, such as the CNO cycle, for comparison
USEFUL FOR

Students of physics, astrophysicists, and anyone interested in understanding stellar nucleosynthesis and the fundamental processes of energy generation in stars.

logearav
Messages
329
Reaction score
0

Homework Statement



Dear members,
In proton proton cycle, Two protons fuse together to form a duetron with positron and nuetrino.
Then duetron combine with another proton to form 2He3, which then combines with another 2He3 to give 2He4
The final reaction is
41H1+2e---> 2He4

Homework Equations





3. The Attempt at a Solution
Only three protons fuse together in the process, then how in the final equation it has been stated 4 protons fuse. For 2He3 to combine with 2He3 , the reaction of proton fusing with another proton, giving duetron, which fusing with another proton, should happen twice. So it is 6 protons fusing. So why its been mentioned only 4 protons fuse to form helium. Please help revered members



 

Attachments

  • 23366.nce001.jpg
    23366.nce001.jpg
    3.4 KB · Views: 476
  • ppf3.gif
    ppf3.gif
    360 bytes · Views: 570
Physics news on Phys.org
logearav said:
3. The Attempt at a Solution
Only three protons fuse together in the process, then how in the final equation it has been stated 4 protons fuse. For 2He3 to combine with 2He3 , the reaction of proton fusing with another proton, giving duetron, which fusing with another proton, should happen twice. So it is 6 protons fusing. So why its been mentioned only 4 protons fuse to form helium. Please help revered members


6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.

Alternatively, you might write a net reaction that doesn't include 2 of the original 6 protons -- in which case you wouldn't have the 2 protons that are left over in the end.
 
6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.

Redbelly98 said:
Alternatively, you might write a net reaction that doesn't include 2 of the original 6 protons -- in which case you wouldn't have the 2 protons that are left over in the end.
Thanks for the reply sir. But i didnt understand the lines quoted above.
 
Is this a homework problem? I am having trouble understanding exactly what the problem is asking, or whether you are just trying to understand for yourself what happens in nuclear fusion.
 
Sir, i am asking to get clarified, because my teacher has not given satisfactory reply. I got 90% of what you said, but i can't understand the lines you have written which i quoted in my previous query.
Thanks again. This is the forum which gives excellent insights to physics, that's why i keep raising my query
 
logearav said:
6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.
Okay, so omit the intermediate products (He-3 nuclei) and write that as
6 1H → 4He + 2 1H (+ energy, positrons, and neutrinos)​
We have hydrogen nuclei on both sides of the reaction, so we can take away 21H from each side. That leaves us with the net reaction.
 
Mr.Redbelly, Fantastic. I got it now. Thank you so much, sir
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
8K
Replies
5
Views
2K
Replies
4
Views
3K
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
Replies
1
Views
4K
  • · Replies 13 ·
Replies
13
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K