How Does the Proton-Proton Cycle Result in the Formation of Helium?

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Homework Help Overview

The discussion revolves around the proton-proton cycle in nuclear fusion, specifically addressing how the fusion of protons leads to the formation of helium. Participants are exploring the steps involved in the cycle and the number of protons that contribute to the final helium product.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the number of protons involved in the fusion process, particularly why the final equation states that four protons fuse when the intermediate steps suggest a different count. There is also discussion about the omission of intermediate products in the net reaction.

Discussion Status

Some participants have provided clarifications regarding the fusion process and the net reaction, while others are still seeking to understand specific points made in the responses. The conversation reflects an ongoing exploration of the topic without a clear consensus on all aspects.

Contextual Notes

One participant mentions that their teacher has not provided satisfactory explanations, indicating a need for further clarification and understanding of the subject matter.

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Homework Statement



Dear members,
In proton proton cycle, Two protons fuse together to form a duetron with positron and nuetrino.
Then duetron combine with another proton to form 2He3, which then combines with another 2He3 to give 2He4
The final reaction is
41H1+2e---> 2He4

Homework Equations





3. The Attempt at a Solution
Only three protons fuse together in the process, then how in the final equation it has been stated 4 protons fuse. For 2He3 to combine with 2He3 , the reaction of proton fusing with another proton, giving duetron, which fusing with another proton, should happen twice. So it is 6 protons fusing. So why its been mentioned only 4 protons fuse to form helium. Please help revered members



 

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logearav said:
3. The Attempt at a Solution
Only three protons fuse together in the process, then how in the final equation it has been stated 4 protons fuse. For 2He3 to combine with 2He3 , the reaction of proton fusing with another proton, giving duetron, which fusing with another proton, should happen twice. So it is 6 protons fusing. So why its been mentioned only 4 protons fuse to form helium. Please help revered members


6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.

Alternatively, you might write a net reaction that doesn't include 2 of the original 6 protons -- in which case you wouldn't have the 2 protons that are left over in the end.
 
6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.

Redbelly98 said:
Alternatively, you might write a net reaction that doesn't include 2 of the original 6 protons -- in which case you wouldn't have the 2 protons that are left over in the end.
Thanks for the reply sir. But i didnt understand the lines quoted above.
 
Is this a homework problem? I am having trouble understanding exactly what the problem is asking, or whether you are just trying to understand for yourself what happens in nuclear fusion.
 
Sir, i am asking to get clarified, because my teacher has not given satisfactory reply. I got 90% of what you said, but i can't understand the lines you have written which i quoted in my previous query.
Thanks again. This is the forum which gives excellent insights to physics, that's why i keep raising my query
 
logearav said:
6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.
Okay, so omit the intermediate products (He-3 nuclei) and write that as
6 1H → 4He + 2 1H (+ energy, positrons, and neutrinos)​
We have hydrogen nuclei on both sides of the reaction, so we can take away 21H from each side. That leaves us with the net reaction.
 
Mr.Redbelly, Fantastic. I got it now. Thank you so much, sir
 

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